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Mila [183]
3 years ago
10

For many​ years, organized crime ran a numbers game that is now run legally by many state governments. The player selects a​ thr

ee-digit number from 000 to 999. There are 1000 such numbers. A bet of $2 is placed on a​ number, say number 115. If the number is​ selected, the player wins ​$1000. If any other number is​ selected, the player wins nothing.
Find the expected value for this game and describe what this means.
Mathematics
1 answer:
VikaD [51]3 years ago
4 0
For many years, organized crime ran a numbers game that is now run legally by many state governments. the player selects a three digit number from 000 to 999. there are 1000 such numbers. a bet of $1 is placed on a number, say number 115. if the number is selected, the player wins $500. if any other number is selected, the player wins nothing. find the expected value for this game and describe what it means 
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Step-by-step explanation:

Step 1: Write our Givens

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Move the constant term ,(the term with no variable) to the right side.

Here we have a negative 7, so we add 7 to both sides

{x}^{2}  + 10x = 7

Next, we take the linear coeffeicent and divide it by 2 then square it.

( \frac{10}{2} ) {}^{2}  = 25

Then we add that to both sides

{x}^{2}  + 10x + 25 = 7 + 25

{ {x}^{2} } + 10x + 25 = 32

Next, we factor the left,

(x + 5)(x + 5) = 32

we got 5 because 5 add to 10 and multiply to 25 as well.

so we get

(x + 5) {}^{2}  = 32

This is called a perfect square trinomial.

Next, we take the square root of both sides

x + 5 = ± \sqrt{32}

± menas that we have a positive and negative solution.

Subtract 5 form both side so we get

x =  - 5± \sqrt{32}

The greater solution is when sqr root of 32 is positive so the answer to that is

\sqrt{32}  - 5 = 0.7

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Step-by-step explanation:

4 0
3 years ago
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Answer:

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sergij07 [2.7K]

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