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Vedmedyk [2.9K]
3 years ago
12

If one of the roots of the quadratice quation x2+kx-12=0is4,what is the value of k?

Mathematics
2 answers:
IceJOKER [234]3 years ago
5 0

Answer:

k = - 1

Step-by-step explanation:

Given that x = 4 is a root then, substitute x = 4 into the equation.

4² + 4k - 12 = 0

16 + 4k - 12 = 0, that is

4k + 4 = 0 ( subtract 4 from both sides )

4k = - 4 ( divide both sides by 4 )

k = - 1

uysha [10]3 years ago
3 0
<h3>Given Equation:</h3>

\huge \purple {\rm { {x}^{2}  + kx - 12 = 0}}

<h3>Value:</h3>

\huge \purple {\rm {x = 4}}

<h3>To Find:</h3>

\huge \purple {\rm {The \: value \: of \: k.}}

<h3>Solution:</h3>

\huge \purple {\rm { {(4)}^{2}  + k(4) - 12 = 0}}

\huge \purple {\rm {or, \: 16 + 4 k - 12 = 0}}

\huge \purple {\rm {or, \: 4k =  - 4}}

\huge \purple {\rm {or, \: k =  \frac{ - 4}{4}  =  - 1}}

<h2>Answer:</h2>

\huge \purple {\sf {The \: value \: of \: k \: is \: -1}}

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