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PIT_PIT [208]
3 years ago
6

Parker spends 1/4 of his earnings on rent and 1/6 of his earnings on entertainment

Mathematics
2 answers:
Oliga [24]3 years ago
7 0
Is that the whole question or is there more?
mote1985 [20]3 years ago
3 0

Answer:

Cool

Step-by-step explanation:

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The point T (-3,-3) is translated 5 units right and 9 units up. What are the coordinates of the resulting point T?
Nadusha1986 [10]
The coordinates are (2, 6)
6 0
3 years ago
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Euguene sold half his books and then bought 17 more he now has 30
FromTheMoon [43]

Answer:

E started with 26 books, sold 13 books, bought 17 more books, and ended with 30 books

Step-by-step explanation:

E has _ books: x

E Sells 1/2 of that _ books: x/2

E buys 17 books and now had 30: (x/2) + 17 = 30

30 - 17 = 13

13 x 2 = 26

x/2 = 26

13 + 17 = 30       <-- checking work

My guess is that x = 13

You didn't clarify what exactly you are looking for but I hope this helps clarify some steps of the problem anyway!

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2 years ago
Julio wanted to borrow $2400 from his parents to buy a scooter. His parents told him they would loan him the money for only 3% s
velikii [3]
$2700 is the answer                                                           
4 0
3 years ago
The GCF of 14 and 35 is _____.
shusha [124]

Answer:

7

Step-by-step explanation:

7x2=14

5x7=35

3 0
3 years ago
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Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad &#10;\begin{array}{llll}&#10;g(x)=&\sqrt{0.5x}\\&#10;&\quad \uparrow \\&#10;&\quad  B&#10;\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
Read 2 more answers
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