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irina1246 [14]
3 years ago
12

The diagonals of rhombus fghj intersect at point k. if side gh is equal to 3x - 10 and side jh is equal to 6x - 19, find x

Mathematics
1 answer:
exis [7]3 years ago
8 0
A rhombus is a square but turned so it looks like a diamond. This means all the sides are equal. With this information we can build an equation to solve for x.

3x - 10 = 6x - 19

1) Subtract 3x from both sides.

-10 = 3x - 19

2) Add 19 to both sides.

9 = 3x

3) Divide both sides by 3.

3 = x

x =3.
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Answer:

m∠1= 79

Step-by-step explanation:

What we have here is two vertical lines and one intersecting point.

The m∠1 and m∠6 are vertical angles, which means that they equal to each other. So, the equation would be: 6x+25= 10x-11.

Step 1- Subtract 6x to both sides.

6x+25= 10x-11

-6x        -6x

25= 4x-11

Step 2- Add 11 to both sides.

25= 4x-11

+11       +11

36= 4x

Step 3- Divide both sides by 4.

<u>36</u>= <u>4x</u>

4     4

x= 9

Now that we know the value of the variable x, substitute it into the equation for m∠1.

m∠1= 10(9)-11

m∠1= 90-11

m∠= 79

<u>Check            </u>

m∠6= 6(9)+25

m∠6= 54+25

m∠6= 79

Since m∠1 and m∠6 are vertical angles, they should equal each other.

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