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3 years ago

I have no idea how this works, but that's not the point here. I really need help on this algebra problem;

2 answers:

4 0

Basically you want to make the equation so that you have
x>something or x<something so basically solve for x or isolate x so

a+bx>cx-d
try to get all the x's on one side
subtract bx from both sides
a>cx-bx-d
add d to both sides
a+d>cx-bx
undistribute
a+d>(x)(c-b)
divide both sides by (c-b)

tada

so the solution is

$\frac{a+d}{c-b}$ >x or
x< $\frac{a+d}{c-b}$

olya-2409 [2.1K]3 years ago

4 0

A+ bx> cx -d
⇒ bx -cx > -a -d
⇒ x(b-c) > -(a+ d) (distributive property)
⇒ x > -(a+ d)/(b -c)

Final answer: x> -(a+ d)/(b -c)~

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Please help! ive been stuck on this for so long and i just keep getting frustrated can someone help walkme through this?

bagirrra123 [75]

For firework launched from height 100ft with initial velocity 150ft/sec, equation made is correct

(a) equation will be $h(t) = -16t^2+150t+100$

(b) Now we have to see when it will land. At land or ground level height h will be equal to 0. So simply plug 0 in h place in equation made in part (a)

$0 = -16t^2 + 150t + 100$

Now we have to solve this quadratic. We will use quadratic formula method to solve this equation.

$t = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

a = -16, b = 150, c = 100.

Plugging these values in quadratic formula we get

$t = \frac{-150 \pm \sqrt{150^2-4(-16)(100)}}{2(-16)}$

$t = \frac{-150 \pm \sqrt{22500+6400}}{-32}$

$t = \frac{-150 \pm \sqrt{28900}}{-32}$

$t = \frac{-150+170}{-32} = \frac{20}{-32} = -0.625$

time cannot be negative so we will drop this answer

then $t = \frac{-150-170}{-32} = \frac{-320}{-32} = 10$

So 10 seconds is the answer for this

(c) To make table simply plug various value for t like t =0, 2, 4, 6, 8 till 10. Plug values in equation mad in part (a) and find h value for each t as shown

For t =0 seconds, $h = -16(0)^2+150(0)+100 = 100 feet$

For t =2 seconds, $h = -16(2)^2+150(2)+100 =336 feet$

For t =4 seconds, $h = -16(4)^2+150(4)+100 = 444 feet$

For t =6 seconds, $h = -16(6)^2+150(6)+100 = 424 feet$

For t =8 seconds, $h = -16(8)^2+150(8)+100 = 276 feet$

For t =10 seconds, $h = -16(10)^2+150(10)+100 = 0 feet$

(d) Axis of symmetry is given by formula

$x = \frac{-b}{2a}$

$t = \frac{-150}{2(-16)} =\frac{-150}{-32} = 4.6875$

t = 4.6875 is axis of symmetry line

(e) x-coordinate of vertex is again given by formula

$x = \frac{-b}{2a}$

so t = 4.6875

then to find y coordinate we will plug this value of t as 4.6875 in equation made in part (a)

For t =4.6875, $h = -16(4.6875)^2+150(4.6875)+100 = 451.563$

so vertex is at (4.6875, 451.563)

(f) As the firework is launched so in starting time is t=0, we cannot have time before t=0 (negative values) practically. Also we cannnot have firework going down into the ground so we cannot have h value negative physically.

6 0

2 years ago

Someone help plss show work

Mazyrski [523]

Answer:

Slope: $\frac{3}{5}$

Y-Intercept: $(0,-5)$

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is $y=mx+b$ . In this case, our equation is already in this form. $m$ is what your slope is. In this case, our

2. To find the y-intercept we look at value $b$ that is in $y=mx+b$ . In this case, $b$ is $-5$ . So, our ordered pair is $(0,-5)$ .

4 0

2 years ago

Read 2 more answers

∠1 and ∠2 are complementary angles. m∠1 is 5y+32 and m∠2 is 7y-14. Find m∠2 & show your work.

Ainat [17]

m<1+m<2=90

$\\ \sf\longmapsto 5y+32+7y-14=90$

$\\ \sf\longmapsto 12y+18=90$

$\\ \sf\longmapsto 12y=72$

$\\ \sf\longmapsto y=6$

m<2=7(6)-14=42-14=28[/tex]

7 0

2 years ago

Read 2 more answers

Evaluate the following expression: -2|9|.<br> -18<br> -11<br> 11<br> 18

Blababa [14]

Answer:

-18 mat-way is good to use

6 0

2 years ago

Let U1, ..., Un be i.i.d. Unif(0, 1), and X = max(U1, ..., Un). What is the PDF of X? What is EX? Hint: Find the CDF of X first,

Kryger [21]

Answer:

$E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}$

Step-by-step explanation:

A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".

We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).

If we select a value $x \in (0,1)$ we want this:

$max(U_1, ....,U_n) \leq x$

And we can express this like that:

$u_i \leq x$ for each possible i

We assume that the random variable $u_i$ are independent and $P)U_i \leq x) =x$ from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this: