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Yuliya22 [10]
3 years ago
14

I have no idea how this works, but that's not the point here. I really need help on this algebra problem;

Mathematics
2 answers:
Ulleksa [173]3 years ago
4 0
Basically you want to make the equation so that you have
x>something or x<something so basically solve for x or isolate x so


a+bx>cx-d
try to get all the x's on one side
subtract bx from both sides
a>cx-bx-d
add d to both sides
a+d>cx-bx
undistribute
a+d>(x)(c-b)
divide both sides by (c-b)

tada


so the solution is

\frac{a+d}{c-b}>x or
x<\frac{a+d}{c-b}




olya-2409 [2.1K]3 years ago
4 0
A+ bx> cx -d
⇒ bx -cx > -a -d
⇒ x(b-c) > -(a+ d) (distributive property)
⇒ x > -(a+ d)/(b -c)

Final answer: x> -(a+ d)/(b -c)~
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Contact [7]

Answer:

a=12

Step-by-step explanation:

A=b*h/2

a=4.8mi*5mi/2

a=24/2

a=12

hope this helps

7 0
3 years ago
(x-1)^2+(2-x)^2-3(x-5)*(x-5)
Natali5045456 [20]

Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

8 0
2 years ago
Factorise 24e^2-28e-12
Helga [31]

Answer:

4(2e - 3)(3e + 1)

Step-by-step explanation:

Given

24e² - 28e - 12 ← factor out 4 from each term

= 4(6e² - 7e - 3) ← factor the quadratic

Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.

product = 6 × - 3 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the e- term

6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )

= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term

= (2e - 3)(3e + 1)

Then

24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form

8 0
3 years ago
Juan bought fruit from the grocery store. The variables below define his purchase. Juan’s bananas cost half as much as apples. W
mixas84 [53]

Answer:

B = \frac{1}{2}A

A = 2B

Step-by-step explanation:

Given

Represent apple with A and Banana with B

Required

Determine the relationship between A and B

From the question, we understand that:

B costs half as much as A

This can be represented as:

B = \frac{1}{2} * A

B = \frac{1}{2}A

Multiply both sides by 2

2*B = \frac{1}{2}A*2

2B = A

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4 0
3 years ago
Which pair of numbers has a GCF of 3. 3and 18, 12 and 18, 8 and 24, 1 and 3
Alinara [238K]
3 and 18 | 12&18 GCF = 6; 8&24 GCF = 4; 1&3 GCF = 3
4 0
2 years ago
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