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nignag [31]
3 years ago
5

The sum of two numbers is 12. The first number,X, is twice the second number,y, which system of equations could be used to find

the two numbers ?
Mathematics
2 answers:
koban [17]3 years ago
6 0

Answer:

y=4, x=8

Step-by-step explanation:

system:

x+y = 12, x=2y

convert to 1 variable, simplify:

2y+y=12

3y=12

y=4

x=2y=4*2=8

Verdich [7]3 years ago
5 0

Answer:

The system of equations are:

x + y = 12

y = 2x  

Solution

x = 4

y = 12

Step-by-step explanation:

Given:

The sum of two numbers is 12. The first number, x, is twice the second number,y

Now we have to form the system of equations to find the solution.

The sum of two numbers is 12.

The first number = x

The second number y = 2x.

x + y = 12 ----(1)

y = 2x  --- (2)

These are the system of equations.

Now let's solve them.

Now plug in y = 2x in the first equation.

x + 2x = 12

Simplifying the like terms, we get

3x = 12

Dividing both sides by 3, we get

x = 4

To find the value of y, that is the second term, we need to plug in x = 4 in the second equation, we get

y = 2*4 = 8

So the first number is 4 and the second number is 8.

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Please solve the whole page please please
Leya [2.2K]

1d) ↑ (Do the same but turned if that's easier)

1a) 199

1b) 193

1c) 217

1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.

2b) 7

2c) 9.5

2d) ↑

2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.

3)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.

[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]

4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.

4) ↑

5)

You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.

In this case the ordered data would be:

45, 45, 50, 55, 60, 70, 70, 75, 80, 85

[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]

45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.

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4 0
2 years ago
I need help on this please help!
Licemer1 [7]

Answer:

(b)0.56

(c)0.38

Step-by-step explanation:

(a)

P(Ben Pass) =0.8

Therefore: P(Ben fails)=1-0.8 =0.2

P(Tom Pass) =0.7

Therefore: P(Tom fails)=1-0.7 =0.3

See attached for the completed tree diagram

(b)Probability that both will pass

P(both will pass)=P(Ben pass and Tom pass)

=P(Ben pass) X P(Tom pass)

=0.8 X 0.7

=0.56

(c)The probability that only one of them will pass

Since either Tom or Ben can pass, we have:

P(only one of them will pass)

=P(Ben pass and Tom fails OR Ben Fails and Tom Pass)

=P(Ben pass and Tom fails)+P(Ben Fails and Tom Pass)

=(0.8 X 0.3) + (0.2 X 0.7)

=0.24 + 0.14

=0.38

8 0
3 years ago
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