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jarptica [38.1K]
3 years ago
8

Is -6.06 an irrational number

Mathematics
2 answers:
slavikrds [6]3 years ago
6 0
No,\ is\ a\ rational\ number.\\\\-6.06=-6\frac{6}{100}=-6\frac{3}{50}\in\mathbb{Q}
Vika [28.1K]3 years ago
4 0
No it isn't an irrational number as it can be expressed as a fraction containing whole numbers.

-6.06

=(-600/100)-(6/100)

=-606/100

=-303/50
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A pile of sand in the shape of a cone has a diameter of 8 in. and a height of 5 in.
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if it has a diameter of 8, that means its radius is half that, or 4.


\bf \textit{volume of a cone}\\\\
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3 years ago
A certain car rental location charges a daily fee as well as a mileage charge. On one trip a businessman rented a car for the da
nikklg [1K]

Answer:

x\approx 267\ miles

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

f(x)=mx+b

For the problem at hand, we must pick the adequate variables according to the data provided.

The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:

c = the charge for renting a car in dollars

x = the distance driven by the businessman in miles

Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:

c = mx+b

We must find the values of m and b with the data provided. Substituting the first point:

79 = 150m+b

Substituting the second point:

63.70 = 65m+b

Both equations form the following system:

\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.

Subtracting both equations:

150m-65m=79-63.70

Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:

85m=15.3

Solving:

m=15.3/85=0.18

From the first equation

79 = 150m+b

Solving for b:

b=79-150m=79-150(0.18) = 52.

The model for the problem is:

c=0.18x+52

Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100

100=0.18x+52

Solve for x:

0.18x+52=100

0.18x=100-52=48

x=48/0.18=266.67

Rounding to the closest integer:

\boxed{x\approx 267\ miles}

7 0
4 years ago
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