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kvasek [131]
2 years ago
5

SOMEONE HELP ME WITH THIS MATH PLS

Mathematics
1 answer:
cluponka [151]2 years ago
6 0

Answer: add

Step-by-step explanation:

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4x2 + 8x – 9 = 0 complet the square
lisov135 [29]
The answer is 1/8. That is the answer for this question.
6 0
3 years ago
Elin has 1/3 hour to warm up for her gymnastics meet. She must complete each 6 different stretches. She spends an equal amount o
Novay_Z [31]

Answer:

1/18 hr per stretch

Step-by-step explanation:

total # of hrs / # of stretches

1/3 hr / 6 stretches = 1/18 hr per stretch

7 0
2 years ago
Read 2 more answers
The measures of two angles of a triangle are 23 and 67. Is the triangle acute, right, or obtuse. Use geometric terms in explanat
Vlada [557]
The angle measures of any triangle = 180 adding 27 and 63. = 90 leaving 90 degrees for the remaining angle therefore the triangle is a right triangle by definition if a triangle has a 90 degree angle it's a right triangle
3 0
3 years ago
Marissa and Callie both have babysitting jobs. Marissa charges $19 plus $1.50 per hour. Callie charges $15 plus $2.75 per hour.
aliya0001 [1]

Answer:

4 hours

Step-by-step explanation:

Write an equation

19 +1.5x < 15+2.75x

Subtarct 15 on both sides

4+1.5x<2.75x

subtract 1.5x on both sides

4< 1.25x

Divide 1.25 on each side

3.2<X

Since they on,y charge per hour so 4 hours

3 0
3 years ago
Read 2 more answers
Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
Keith_Richards [23]

Answer:

  32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

  C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

  ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

  ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

__

For t=20, this is ...

  ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

  (150 -C)/(60 -C) = 4.225

  1 +90/(60 -C) = 4.225

  C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

7 0
2 years ago
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