SOMEONE HELP ME WITH THIS MATH PLS

A comet travels along a parabolic path around the Sun. The Sun is the focus of the path. When the comet is at the vertex of the

AlladinOne [14]

Remember that for a function of the form $y=a x^{2}$ , a parabola, the focus will be: $(0, \frac{1}{4a} )$ .
We know that the vertex of the parabola is (0,0), and the sun is the focus of the parabola; we also know that the focus is in the positive y-axis and when the comet is as its vertex, the distance between them is 60'000.000 km; therefore the focus of our parabola is (0, 60'000.000).
Now that we know the focus, we can find $a$ using the focus of the parabola:
$\frac{1}{4a} =60'000.000$
$1=(60'000.000)(4a)$
$1=240'000.000a$
$a= \frac{1}{240'000.000}$

Now, the only thing left is replacing the value of $a$ in our equation $y=a x^{2}$ :
$y=( \frac{1}{240'000.000)} ) x^{2}$
$y= \frac{ x^{2} }{240'000.000}$

We can conclude that the equation that represents the path of the comet is $y= \frac{ x^{2} }{240'000.000}$

5 0

3 years ago

Please Help me with the problem please!

evablogger [386]

Answer:

35%

total number of 11th graders = 32+18 = 50

calculating percentage:

18÷50×100

= 36%

4 0

3 years ago

Pergunta 5 You need to fill a football with air to play with it. You know that your pump expels air at speed of 8.2 ft/s. The ne

ra1l [238]

The volume flow rate of the air being pumped into the football will be given by:
Q=V*A
Where
V=Speed
A=Area
You know that your pump expels air at speed of 8.2 ft/s
The area of The needle of your pump is
A=pi*r^2=pi*((4.5/1000)*(3.28))^2=0.00068442 ft^2
Finally
Q=V*A=(8.2 ft/s)*(0.00068442ft^2)=0.005612243 ft^3/s

8 0

3 years ago

Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematic

pishuonlain [190]

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): $\mu \geq 2000$

Alternative hypothesis (H1): $\mu$

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): $\mu \geq 2000$

Alternative hypothesis (H1): $\mu$

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

7 0

3 years ago

Solve ln 2 + ln x = 5 . Round to the nearest thousandth, if necessary. show work please

Paraphin [41]

$\ln 2 + \ln x = 5\\\\\implies \ln(2x) = 5\\\\\implies 2x = e^5\\\\\implies x = \dfrac{e^5}2 = 74.207$

6 0

3 years ago