Answer:
![x\approx 267\ miles](https://tex.z-dn.net/?f=x%5Capprox%20267%5C%20miles)
Step-by-step explanation:
<u>Linear Modeling</u>
Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.
The linear function can be expressed in the slope-intercept format:
![f(x)=mx+b](https://tex.z-dn.net/?f=f%28x%29%3Dmx%2Bb)
For the problem at hand, we must pick the adequate variables according to the data provided.
The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:
c = the charge for renting a car in dollars
x = the distance driven by the businessman in miles
Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:
![c = mx+b](https://tex.z-dn.net/?f=c%20%3D%20mx%2Bb)
We must find the values of m and b with the data provided. Substituting the first point:
![79 = 150m+b](https://tex.z-dn.net/?f=79%20%3D%20150m%2Bb)
Substituting the second point:
![63.70 = 65m+b](https://tex.z-dn.net/?f=63.70%20%3D%2065m%2Bb)
Both equations form the following system:
![\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Bmatrix%7D150m%2Bb%3D79%5C%5C%2065m%2Bb%3D63.70%20%5Cend%7Bmatrix%7D%5Cright.)
Subtracting both equations:
![150m-65m=79-63.70](https://tex.z-dn.net/?f=150m-65m%3D79-63.70)
Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:
![85m=15.3](https://tex.z-dn.net/?f=85m%3D15.3)
Solving:
![m=15.3/85=0.18](https://tex.z-dn.net/?f=m%3D15.3%2F85%3D0.18)
From the first equation
![79 = 150m+b](https://tex.z-dn.net/?f=79%20%3D%20150m%2Bb)
Solving for b:
![b=79-150m=79-150(0.18) = 52.](https://tex.z-dn.net/?f=b%3D79-150m%3D79-150%280.18%29%20%3D%2052.)
The model for the problem is:
![c=0.18x+52](https://tex.z-dn.net/?f=c%3D0.18x%2B52)
Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100
![100=0.18x+52](https://tex.z-dn.net/?f=100%3D0.18x%2B52)
Solve for x:
![0.18x+52=100](https://tex.z-dn.net/?f=0.18x%2B52%3D100)
![0.18x=100-52=48](https://tex.z-dn.net/?f=0.18x%3D100-52%3D48)
![x=48/0.18=266.67](https://tex.z-dn.net/?f=x%3D48%2F0.18%3D266.67)
Rounding to the closest integer:
![\boxed{x\approx 267\ miles}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%5Capprox%20267%5C%20miles%7D)