Ask question

Ask question

All categories

2 years ago

9

5) A rectangular piece of paper is 10cmn long and 5cm broad.find its area,

1 answer:

ivann1987 [24]2 years ago

3 0

Area=L•W
10cm•5cm= 50cm^2

You might be interested in

2/5 g+3h -6 when g=10 h=6

motikmotik

<h3>hello!</h3>

let's evaluate this expression

$\pmb{\displaystyle\frac{2}{5}g+3h-6 }$

$\pmb{\displaystyle\frac{2}{5} *10+3(6)-6}$

$\pmb{\displaystyle\frac{2}{5} *10+18-6}$

$\pmb{\displaystyle\frac{2}{5} *10+12}$

Multiply:

$\pmb{\displaystyle\frac{2}{5} *\frac{10}{1} =\frac{20}{5} =4}$

Final Step:-

$\pmb{4+12}$

$\pmb{16}$

======================================================

<h3>note:-</h3>

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I'll comment and/or edit my answer :)

5 0

2 years ago

Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.

borishaifa [10]

The answer is c

hope that helps :)))

5 0

2 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

SOMEONE PLS HELPPP FASTTT<br>The tree height is equal to?

laiz [17]

Answer:

Step-by-step explanation:

Multiple 4*6

Get that answer then divide the answer u got for 4*6 and divide that with 60 which equals 24÷60

8 0

3 years ago

Train X is traveling at a constant speed of 30 miles per hour and Train Y is traveling at a constant speed of 40 miles per hour.

topjm [15]

Answer:

3.5 hours

Step-by-step explanation:

Speed of train X=30 mph

Speed of train Y=40 mph

Relative speed When the two trains travelling in same direction

Relative speed=40-30=10 mph

Total distance =25+10=35 miles

We have to find the time when train Y is 10 miles ahead of train X.

We know that

Time= $\frac{Distance}{Relative\;speed}$

Using the formula

Then, we get

Time= $\frac{35}{10}=3.5 hours$

Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.

7 0

3 years ago

Read 2 more answers