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7nadin3 [17]
3 years ago
10

Can someone please help ?

Mathematics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

sorry i cant read

Step-by-step explanation:

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Please help asap! I will mark brainliest for correct answer!!
solmaris [256]

Answer: Do the math, the positive solution

t = 5.0495 seconds (If it's wrong sorry, I havent done a problem like this one in awhile!)

Step-by-step explanation:

6 0
3 years ago
The table below shows the amount of money, in cents, Celine had in her savings account after different number of years: Years 2
stiv31 [10]
It increases exponentially by 4 each year
so you multiply 12 by 4, 9 times to get <span>786,432</span>
4 0
4 years ago
5^3+5-6(4)<br><br> HELP FAST I’M IN CLASS
vodomira [7]

To solve: 5^3+5-6(4)

5^3+5-6(4) < first step, 5 to the third power is 125

125 + 5 - 6(4) < next step, 6(4) or 6 x 4 is 24

125 + 5 - 24 < third step, add/subtract based off what comes first.

130 - 24 < final step. 130 - 24 = 106

106 is your final answer.

5 0
3 years ago
What is the expression for 10 less than half a number is 27
mr_godi [17]

\frac{1}{2} n - 10 = 27

let the number be 10 then half this number is \frac{1}{2} n and 10 less is

\frac{1}{2} n - 10

this is 27 meaning equal to 27 thus equation is

\frac{1}{2} n - 10 = 27



4 0
4 years ago
Triangle A B C is shown. Angle C A B is a right angle. Angle A B C is 30 degrees and angle B C A is 60 degrees. The length of A
scoundrel [369]

Answer:

SinB = 1/2, SinC = √3/2 and

TanC = √3

Step-by-step explanation:

The question lacks options. Find the complete question in the comment section.

Given triangle ABC, we will use the SOH, CAH, TOA trig identity to get the correct ratio.

Given the hypotenuse BC = 18 and one of the other two sides AC = 9, we can get the third side AB using Pythagoras theorem.

BC² = AC²+AB²

18² = 9²+AB²

2² = 1²+AB²

AB² = 4-1

AB² = 3.

AB = √3

Making <ABC as reference angle, AC will be opposite and AB will be the adjacent.

Sin<ABC = opp/hyp = AC/BC

Sin<ABC = 1/2

Cos<ABC = adj/hyp = AB/BC

Cos<ABC = √3/2

Tan<ABC = opp/adj = AC/AB

Tan<ABC = 1/√3

Making <BCA as reference angle, AB will be opposite and AC will be the adjacent.

Sin<BCA = opp/hyp = AB/BC

Sin<BCA = √3/2

Cos<BCA = adj/hyp = AC/BC

Cos<BCA = 1/2

Tan<BCA = opp/adj = AC/AB

Tan<BCA = √3

Frim the above calculation, the correct options are sin<ABC = 1/2, Sin<BCA = √3/2 and Tan<BCA = √3

8 0
3 years ago
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