Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
6=3 : 16=6 14=6 that should be right
The answer is -2,2 for this problem
Answer: 1:3
Step-by-step explanation: You would divide both sides by 6 and get 1:3 poodles to beagles