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3 years ago

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plllllllllllllllllllllllllllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz help me due in3 hours

1 answer:

evablogger [386]3 years ago

7 0

the answer is D

reason: ration of freshmen to sophmores is 17 to 19, for other way around, flip the num ber

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Please help me with the question first get brainliest

CaHeK987 [17]

The answer is the last one

6 0

3 years ago

Read 2 more answers

Find the values of c such that the area of the region bounded by the parabolas

evablogger [386]

For there to be a region bounded by the two parabolas, you first need to find some conditions on $c$ . The two parabolas must intersect each other twice, so you need two solutions to

$16x^2-c^2=c^2-16x^2$

You have

$32x^2=2c^2\implies 16x^2=c^2\implies x=\pm\dfrac{|c|}4$

which means you only need to require that $c\neq0$ . With that, the area of any such bounded region would be given by the integral

$\displaystyle\int_{-4|c|}^{4|c|}\bigg((c^2-16x^2)-(16x^2-c^2)\bigg)\,\mathrm dx$

since $c^2-16x^2>16x^2-c^2$ for all $c\neq0$ . Now,

$\displaystyle\int_{-|c|/4}^{|c|/4}\bigg((c^2-16x^2)-(16x^2-c^2)\bigg)\,\mathrm dx=2\int_0^{|c|/4}(2c^2-32x^2)\,\mathrm dx$

by symmetry across the y-axis. Integrating yields

$\displaystyle2\int_0^{|c|/4}(2c^2-32x^2)\,\mathrm dx=4\int_0^{|c|/4}(c^2-16x^2)\,\mathrm dx$
$=4\left[c^2x-\dfrac{16}3x^3\right]_{x=0}^{x=|c|/4}$
$=c^2|c|-\dfrac{|c|^3}3$
$=\dfrac{2|c|c^2}3=144$
$|c|c^2=216$

Since $216=6^3$ , you have $c=\pm6$ .

3 0

3 years ago

Markus sent a chain letter to his friends, asking them to forward the letter to more friends. The relationship between the elaps

Ray Of Light [21]

Answer:

Every day, 43% percent of people are added from the total number of people who receive the email

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the total number of people who receive the email

t is the time in days

a is the initial value

r is the rate of change

we have

$P(t)=6(1.43)^t$

so

$a=6$ ---> initial number of people who receive the email

$(1+r)=1.43$

solve for r

$r=1.43-1\\r=0.43$

Convert to percentage

$0.43(100)=43\%$

so

The daily percent change in the number of people who receive the email. every day is 43%

therefore

Every day, 43% percent of people are added from the total number of people who receive the email

4 0

3 years ago

Read 2 more answers

Determine the slope of a

AysviL [449]

Answer:

<em>m</em> = 3/5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Coordinates (x, y)
Slope Formula: $\displaystyle m = \frac{y_2-y_1}{x_2-x_1}$
Perpendicular lines are the negative reciprocal of the given line

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point G(-2, 3)

Point H(1, -2)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

<em />

<em>Line GH</em>

Substitute in points [Slope Formula]: $\displaystyle m = \frac{-2-3}{1--2}$
[Fraction] Subtract: $\displaystyle m = \frac{-5}{3}$

<em>Perpendicular line</em>

Negative: $\displaystyle m = \frac{5}{3}$
Reciprocate: $\displaystyle m = \frac{3}{5}$

4 0

3 years ago

Please help and answer it in a sentence :)

Alexandra [31]

Answer:

x = $1 & y = $2.

Each doughnut cost $1 and hot chocolate cost $2.

7 0

2 years ago