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Mnenie [13.5K]
3 years ago
8

Suppose that there are 630 seats in a row. If the person to be seated is needed to sit next to someone, then what is the fewest

number of seats that need to be occupied?
Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

Its 210

Step-by-step explanation:

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A Hot air balloon can hold 90,000 cubic feet of air. It is being inflated at a rate of 6,000 cubic feet per minute . The total c
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\bf \stackrel{\textit{cubic feet of air}}{\stackrel{\textit{dependent}}{a(t)}}\qquad \stackrel{\stackrel{\textit{time in minutes}}{independent}}{t}~\hspace{7em}a(t)=6000t


the "t" variable is independent, namely it can change values "freely", and a(t) is dependent, because it depends on those values on "t" to get its own value.

if we make a table of values for minutes, we know the balloon is inflating at 6000 ft³ each passing minute.

1 minute......................... 6000(1) ft³

2 minutes......................6000(2) ft³

3 minutes......................6000(3) ft³

4 minutes......................6000(4) ft³

t minutes......................6000(t) ft³


before getting in the domain and range, let's find out how much air after 6 minutes.

a(6) = 6000(6)

a(6) = 36000 ft³.


now, what domain, namely values for "t" make sense?

well, we know the balloon can only hold up to 90000 ft³, and on every passing minute is filling up by 6000 ft³, after how many minutes will it be filled up?

90000/6000 = 15, after 15 minutes.

so at 0 minutes, t = 0, the balloon is empty, and 15 minutes later, t = 15, the balloon is filled up, [ 0 , 15 ].


what values for the range, namely a(t), makes sense?

well, we know when the balloon is empty is holding 0 ft³, and when is full it has 90000 ft³, [0 , 90000].

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The answer is either x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\ or x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}

To solve: Let's solve your equation step-by-step.

5x2+5x−x2−x=2004

Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

4x2+4x−2004=2004−2004

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Step 3: Use quadratic formula with a=4, b=4, c=-2004.

x= −b±√b2−4ac /2a

x= −4±√32080 /8

x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\ or x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}

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