The depth of the swimming pool that is filled to the top is; 4 m
<h3>Snell's Law</h3>
I have attached a schematic diagram showing this question.
The correct width of the pool is 4 meters. Thus; w = 4 m
Incident Angle; θ₁ = 20°
A right angle is 90° and so the angle θ₂ is calculated from;
θ₂ = 90° - θ₁
θ₂ = 90° - 20°
θ₂ = 70°
We can use snell's law formula to find θ₃.
Thus;
n₁sinθ₂ = n₂sinθ₃
where;
n₁ is refractive index of air = 1
n₂ is refractive index of water = 1.33
Thus;
1*sin 70 = 1.33*sin θ₃
sin θ₃ = (sin 70)/1.33
Solving this gives;
θ₃ = 44.95°
By usage of trigonometric ratios we can find the depth of the pool using;
w/d = tan θ₃
Thus;
d = w/(tan θ₃)
d = 4/(tan 44.95)
d ≈ 4 m
Read more about Snell's Law at; brainly.com/question/10112549
Answer:
I think i don't really know its been awhile for me.
Step-by-step explanation:
But i think you do 2 x 10 and what ever you get from that you multiply by 5 and what get from that you divide by 24.
I may not be right.
So please don't hate i tried.
Answer:
The Answer is: y = - 2x + 8.
the y-intersept is 8, and the slope is -2x
Let Peters age be x
Phil's age is 1/5x+7---------------------------(i)
Phil's age can also be calculated as
4(1/5x+7)=2x-2--------------------------------(ii)
So,
4/5x+28=2x-2
28+2=2x-4/5x
30=10/5x-4/5x
30=6/5x
x=30*

x=25