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Travka [436]
3 years ago
9

What is the first step in solving -5x-1/6>3/2

Mathematics
2 answers:
viktelen [127]3 years ago
7 0

Answer:

A is the correct answer

Step-by-step explanation:

Add 1/6 to both sides

4vir4ik [10]3 years ago
4 0

You add 1/6 to both sides

Step-by-step explanation:

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*GIVING BRAINLIEST 50POINTS*
PilotLPTM [1.2K]

Answer:

1.x^7

2.x^10

3.a^2

4. 5

Step-by-step explanation:

1. x^(5+2)=x^7

2.x^(5*2)=x^10

3.a^(5-3)=a^2

4. 5 * 1=5

8 0
3 years ago
Read 2 more answers
If Upper A equals StartSet x | x is an even integer EndSet commaA={x | x is an even integer}, Upper B equals StartSet x | x is a
White raven [17]

Answer:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Step-by-step explanation:

A={x | x is an even integer}

B={x | x is an odd integer},

C={2, 3, 4, 5},

D={8, 9, 10, 11}.

A union of two or more sets is the collection of the members of the sets in a set without repeating any element.

Given sets C and D above, the union of the two sets is the set:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Note: The Intersection is the collection of sets that are common to C and D. in this case no element is common, therefore the intersection is a Null Set.

8 0
3 years ago
Plz help will mark brainliest
Ganezh [65]

Answer to Problem 1: 53

Answer to Problem 2: x  ≥  2

6 0
3 years ago
How can i get answers by factors of 256​
kobusy [5.1K]

Answer: Factor Pairs of 256

1 x 256 = 256.

2 x 128 = 256.

4 x 64 = 256.

8 x 32 = 256.

16 x 16 = 256.

Step-by-step explanation: These all equal up to 256

5 0
3 years ago
Which is equivalent to √60n^11/256n^4 after it has been simplified completely? Assume n =0
motikmotik

Answer:

\large\boxed{\dfrac{n^3}{8}\sqrt{15n}}

Step-by-step explanation:

\sqrt{\dfrac{60n^{11}}{256n^4}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\ \text{and}\ \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\\\=\sqrt{\dfrac{60}{256}n^{11-4}}=\dfrac{\sqrt{60n^7}}{\sqrt{256}}=\dfrac{\sqrt{4n^{6+1}\cdot15}}{16}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{\sqrt{4n^6\cdot15n}}{16}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\dfrac{\sqrt{4n^{3\cdot2}}\cdot\sqrt{15n}}{16}\qquad\text{use}\ (a^n)^m=a^{nm}

=\dfrac{\sqrt{4(n^3)^2}\cdot\sqrt{15n}}{16}=\dfrac{\sqrt{4}\cdot\sqrt{(n^3)^2}\cdot\sqrt{15n}}{16}=\dfrac{2\!\!\!\!\diagup^1\sqrt{15n}}{16\!\!\!\!\!\diagup_8}=\dfrac{n^3\sqrt{15n}}{8}

5 0
3 years ago
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