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rjkz [21]
3 years ago
12

An oval track is made by enclosing semicircles on each end of a 60 m by 120 m rectangle. Find the area enclosed by the track. Us

e 3.14 for pi.
Mathematics
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer:

10026 m²

Step-by-step explanation:

Since there are two semicircles attached to the rectangle, we can just say that that is one circle.

1. The area of the rectangle:<em> length * width = 60 * 120 = 7200 m²</em>.

2. The area of the circle: πr²

a. The radius of the circle: Since the circle is attached to the end of the rectangle, that means that the diameter would be the same length as the width. So, it would be 60 m, therefore, <em>the radius is 30 m</em>.

b. πr² = 3.14*30² = 3.14*900 = <em>2826 m²</em>.

3. Total: 2826 + 7200 = 10026 m².

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A coffee shop collected the following information regarding purchases from 110 of its customers 59 purchased coffee 39 purchased
Andrej [43]

Answer:

Let X be the number of customer purchased coffee

Let Y be the number of customer purchased donuts

Then X\cap Y is the number of customer purchased both coffee and donuts

X\cup Y  is the number of customer purchased both coffee or donuts

<em><u>The Number of customers purchased  only Coffee:</u></em>

Number of customers purchased  only donuts =n(X -Y)

n( X -Y) = n(X) - n(X \cap Y)

n(X-Y) = 59 -16

n(Y - X) = 43

<em><u>The Number of customers purchased  only donuts:</u></em>

Number of customers purchased  only donuts =n(Y -X)

n(Y - X) = n(Y) - n(X \cap Y)

n(Y - X) = 39 -16

n(Y - X) = 23

<u>The Number of customers did not purchase either of these items:</u>

Number of customers did not purchase either of these items = n(X\cup Y)^{\prime}

First lets find   n(X\cup Y)

n(X\cup Y) = n(X) +  n(Y) - n( X \cap Y)

n(X\cup Y) = 59 + 39 - 16

n(X\cup Y)  = 82

n(X\cup Y)^{\prime}  =110 -  n(X\cup Y)  = 28

5 0
4 years ago
Gina has $ 12,000 in investments, has an $ 800 outstanding credit card bill, owes $ 5600 on her car payment, and has $ 15,000 le
ElenaW [278]

Answer: $33,400 ✌️

A liability is anything you owe or any debt you have to pay back.

4 0
3 years ago
A large university accepts ​60% of the students who apply. Of the students the university​ accepts, 50​% actually enroll. If 10,
prisoha [69]

we need to find 1% of 10000 first

so we divide 10000:100= 100 (that's 1%)

to find the 60% which will be accepted we multiply 100 × 60 = 6000 students accepted

of those 6000 we need to find 50% which is ½ so we basically just divide by 2, aka 6000 : 2 = 3000 people which will be enrolled

3 0
3 years ago
For question 19 and 20 can you please solve! Ill award 50 points to however does it! Thank you soo much!
Fittoniya [83]

Answer:

Step-by-step explanation:

19.

2x^2+x-6=0

x^2+x-12=0

(x+2)(2x-3)=0

x=-2,3/2

20.

x^2+8x+15=0

(x+3)(x+5)=0

x=-3,-5

4 0
3 years ago
Read 2 more answers
-7/10+7/15+1/-20+-9/10+11/15+11/-20 <br> what is the answer please help me .....!!!!
Nat2105 [25]

Answer:

-1

Step-by-step explanation:

-7/10+7/15+1/-20+-9/10+11/15+11/-20

= -7/10 + -9/10 + 7/15 + 11/15 + 1/-20 + 11/-20

= -16/10 + 18/15 + 12/-20

= -8/5 + 6/5 + -3/5

= (-8+6-3)/5

= -5/5

= -1

7 0
3 years ago
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