Answer:
Step-by-step explanation:
Rhombus is a two dimensional shape. So it doesn't have volume.
Area of rhombus = (pq)/2
Here p & q are the diagonals
Answer:
As per the given statement:
The distance from jack eyes to the top of the tower = 50.64 m
Also, jack and john eyes are 1.5 m from the ground.
Labelled diagram as shown in the attachment
Let BC = x m be the distance of the jack from the base of the tower and
AG = y m be the distance above 1.5 m from the the ground.
Using tangent ratio:
![\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7B%5Ctext%7BOpposite%20side%7D%7D%7B%5Ctext%7BAdjacent%20side%7D%7D)
In triangle AGE;
![\tan 40^{\circ} = \frac{AG}{EG}](https://tex.z-dn.net/?f=%5Ctan%2040%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7BAG%7D%7BEG%7D)
Here, AG = y m and EG = 20+x m
then;
![\tan 40^{\circ} = \frac{y}{20+x}](https://tex.z-dn.net/?f=%5Ctan%2040%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7By%7D%7B20%2Bx%7D)
or we can write this as;
........[1]
Similarly, in AGF;
![\tan 60^{\circ} = \frac{AG}{FG}](https://tex.z-dn.net/?f=%5Ctan%2060%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7BAG%7D%7BFG%7D)
then;
![\tan 60^{\circ} = \frac{y}{x}](https://tex.z-dn.net/?f=%5Ctan%2060%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7By%7D%7Bx%7D)
![\sqrt{3} = \frac{y}{x}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%3D%20%5Cfrac%7By%7D%7Bx%7D)
or
......[2]
Substitute equation [2] into the equation [1], to solve for x;
or
Using distributive property: ![a\cdot (b+c) = a\cdot b+ a\cdot c](https://tex.z-dn.net/?f=a%5Ccdot%20%28b%2Bc%29%20%3D%20a%5Ccdot%20b%2B%20a%5Ccdot%20c)
we have;
![1.732x = 16.8 + 0.84x](https://tex.z-dn.net/?f=1.732x%20%3D%2016.8%20%2B%200.84x)
Subtract 0.84 x from both sides we get;
![0.892x = 16.8](https://tex.z-dn.net/?f=0.892x%20%3D%2016.8)
Divide both sides by 0.892 we get;
![x \approx 18.8 m](https://tex.z-dn.net/?f=x%20%5Capprox%2018.8%20m)
Therefore, 18.8 meter johns from the base of the tower.
You can do 14/16 or 3.5/4
See the attached picture:
Answer: 12.034 yards
Step-by-step explanation:
Given the following :
Height to which egg is protected = 11 meters
Converting this height of 11 meters to yards
Let the height in yards = h
1 meter = 1.094 yards
11 meters = h
(1 * h) = (11 * 1.094)
h = 12.034 yards
Hence, the height in yards to which egg is protected = 12.034 yards