The set of all possibilities is called sample space and is denoted by S.
So, S = {NBD, NDB, BDN, BND, DBN, DNB} and n(S) = 8
and we need to find the probability of NBD
E = {NBD} and n(E) = 1
The probability of an even is defined by p(E) = 
Hence, p(E) = 
Answer: f(-2)=6.
Explanation: Since -2 is less than 1 you plug it into the top equation for -(-2)+4 = 2+4 =6
Answer:
<h2>
The right option is twelve-fifths</h2>
Step-by-step explanation:
Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.
Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;
Tan (A) = opp/adj
Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;
tan(A) = BC/AC
tan(A) = 24/10
tan(A) = 12/5
The right option is therefore twelve-fifths
<h2>
Answer:</h2>
x = 1, -4
Step-by-step explanation:
Find the roots of x:
2 + 3
x − 4 = 0 by solving for x
.
What is the domain of the function y=3 in x graphed below?
Domain is x>0, ln (0) is undefined and there is no negative ln.
