let length of one piece = x
length of other piece = 236-x
one piece is three times the length of the other
x=3(236-x)
x=708-3x
4x=708
x=177
so first piece is 177 inches long and second piece is (236-177)= 59 inches long
X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
Answer:
0.84
Step-by-step explanation:
Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:
P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95
We are to find out P(A'UB)
We have
![P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84](https://tex.z-dn.net/?f=P%28A%27UB%29%20%3D%20P%28A%27%29%2BP%28B%29-P%28A%27%20%5Cbigcap%20B%29%5C%5C%3D%201-P%28A%29%20%2BP%28B%29-%5BP%28B%29-P%28A%20%5Cbigcap%20B%29%5D%5C%5C%3D%201-0.86%2B0.79-P%28B%29%2B%5Btex%5DP%28A%27UB%29%3D0.14%2B0.79-0.79%2B0.70%5C%5C%3D0.84)
P(A \bigcap B)[/tex]
Answer:
13
Step-by-step explanation:
To solve this, lets first find the number of footballs he still needs:
75-24 = 51
Now to find the number of packages, divide by 4, since there are 4 balls per package:
51/4 = 12 Remainder 3
Since there is a remainder, and the Coach MUST have at least 75, then we need to add a package to include the remainder:
12 + 1 = 13 Packages
