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2 years ago

What is the value of 3x^2– 7x + 9 when x = 4?

Mathematics

1 answer:

xxMikexx [17]2 years ago

6 0

Answer:

Step-by-step explanation:

just substitute x with 4 in the equation :)

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20 points.<br> Please answer and explain if possible.<br> Multiply.<br> -2y^2 * xy^4

Readme [11.4K]

When the bases are the same, you can combine the exponents.

x³ [x is where the base is]

For example:

x³ · y² = x³y² You can't simplify this anymore because they have different bases/variables

[when you multiply a variable with an exponent by a variable with an exponent, you add the exponents together] so:

x² · x³ = $x^{2+3}=x^5$

[when you multiply a variable with an exponent by an exponent, you multiply the exponents together] so:

(x³)²= $x^{3*2}=x^6$

$-2y^2*xy^4=-2x(y^{2+4})=-2xy^6$

4 0

3 years ago

Read 2 more answers

SOMEBODY PLSSSSSSS HELP!! :(

Lelechka [254]

Answer:

What's your question?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus , which is 46feet above the vertex of th

uranmaximum [27]

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

=(18)

=400−324=76

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

−

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

−

324

=1 .

7 0

2 years ago

2x - 10 = 20 pls help?

Anettt [7]

Answer:

x=15

Step-by-step explanation:

2x-10=20

2x-10+10=20+10

2x=30

2x/2 = 30/2

x=15

3 0

2 years ago

Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer

QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0

2 years ago