First: The student rotated the figure 90° clockwise.
Second: The student reflected across the x-axis.
Answer: Option C. <span>The student rotated the figure 90° clockwise rather than 90° counterclockwise.</span>
Answer:
-7c
Step-by-step explanation:
Answer: Option D.
Step-by-step explanation:
To solve this exercise you must keep on mind the Angle at the Center Theorem.
According to the Angle at the Center Theorem, an inscribed angle is half of the central angle.
Therefore, given in the inscribed angle m∠BAC=35°, you can calculate the central angle m∠EFD as following:
- Solve for EFD.
- When you substitute values. you obtain:
Answer:
The correct options are;
D. Triangles ABC and A'B'C' are congruent
E. Angle ABC is congruent to angle A'B'C'
F. Segment BC is congruent to segment B'C'
H. Segment AQ is congruent to segment A'Q'
Step-by-step explanation:
The given information are;
The angle of rotation of triangle ABC = 60°
Therefore, given that a rotation of a geometric figure about a point on the coordinate plane is a form of rigid transformation, we have;
1) The length of the sides of the figure of the preimage and the image are congruent
Therefore;
BC ≅ B'C'
2) The angles formed by the sides of the preimage are congruent to the angles formed by the corresponding sides of the image
Therefore;
∠ABC ≅ ∠A'B'C'
3) The distances of the points on the figure of the preimage from the coordinates of the point of rotation are equal to the distances of the points on the figure of the image from the coordinates of the point of rotation
Therefore;
Segment AQ ≅ A'Q'.
Answer: uh I think its a carrot, sorry i hope this could maybe help :)
Step-by-step explanation:
