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lana66690 [7]
3 years ago
5

Chocolate cake for 6 people needs 150g of flour, 150g of sugar, 120g of cocoa and 3 eggs. Emma has 8 eggs, 450g flour, 380g suga

r, 300g of cocoa. What’s the maximum number of people that she can make for a cake?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0
First you would need to dive what you have of each ingredient by how much you need for 6 people.

Flour: 450 ÷ 150 = 3
Sugar: 380 ÷150 = 2 
Cocoa: 300 ÷ 120 = 2.5
Eggs: 8 ÷ 3 = 2.7

then you look at the total batches each could make and average it to 2 batches. then multiply 6 by 2.

6×2= 12 

so all together, the maximum amount of people you can make for is 12.
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9. If J= 12, what is J/3 + 3?
3241004551 [841]

Answer: the answer is 7.

Step-by-step explanation:

you take 12, divide it by 3 to get 4, then you add 3 to get 7.

6 0
3 years ago
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Which equation correctly describes the relationship between the measures of the angle and arcs formed by the intersecting secant
marishachu [46]
Angle m∠1 if formed by a tangent and  secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant 
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)

Answer: m∠1=1/2(mJK-KL)
3 0
3 years ago
A researcher studying public opinion of proposed Social Security changes obtains a simple random sample of 35 adult Americans an
Y_Kistochka [10]

Answer: a) 15, b) 1.

Step-by-step explanation:

A researcher studying public opinion of proposed social security changes obtains a simple random sample of 35 adult Americans and asks them whether or not they support the proposed changes. To say that the distribution of the sample proportion of adults who respond yes, is approximately normal, how many more Americans does the researcher need to sample in the following cases?

(a)    10% of all adult Americans support the changes

Here, np>5\ and\ n(1-p)>5

And , p=0.10

So, consider the equality, to find the value of 'n'.

np=5\\\\n\times 0.10=5\\\\n=\dfrac{5}{0.10}\\\\n=50

So, there are 50-35=15 more adult Americans needed.

(b)   15% of all adult Americans supports the changes

Here, p=0.15

So, again we get that

np=5\\\\n\times 0.15=5\\\\n=\dfrac{5}{0.15}\\\\n=33.33\\\\n\approx 34

So, there are 35-34=1 more adult Americans needed.

Hence, a) 15, b) 1.

5 0
3 years ago
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
2 years ago
) Asuka travels at an average speed of 50 mph for 20 miles.
Anuta_ua [19.1K]

Answer: 41.86 miles/hour

Step-by-step explanation:

Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [<em>in brackets</em>].

MPH MILES     HOURS

 50            20      [<em>0.4]</em>

 [<em>40</em>]    <u>70</u>      <u>1.75</u>

Totals   90 miles   2.15 hours

Average = 90 miles/2.15 hours

     41.86 mph

5 0
3 years ago
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