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KengaRu [80]
3 years ago
13

During an auditory transduction, ion flow varies across the _____.

Chemistry
1 answer:
Sindrei [870]3 years ago
7 0
During an auditory transduction, ion flow varies across the hair cell membrane.
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Pcl3+H2O=H3PO3+Hcl=?​
beks73 [17]

Answer:

PCl3 + 3H2O → HPO(OH)2 + 3HCl. Phosphorus(III) chloride react with water to produce phosphorous acid and hydrogen chloride.

Explanation:

7 0
3 years ago
Read 2 more answers
If a question cannot be tested and observed, it cannot be answered with science. (2 points) True or False?
boyakko [2]

Answer:

True

Explanation:

If a question cannot be tested and observed, it cannot simply be answered by science.

Science works with observable and testable ideas and not on metaphysics.

  • Science presents a methodical approach into investigating phenomenon and answering likely questions in a logical manner.
  • The body of facts and data gathered through observations and tests are used to ramify the conclusion of a scientific study.
  • Without such, it is impossible to do the work of science.
3 0
3 years ago
three moles of sodium carbonate are mixed with two moles of lead nitrate in aqueous solution, leading to formation of a solid pr
aleksandrvk [35]

There are 4 moles of spectator ions that remain in solution.

The equation of the reaction is;

Na2CO3(aq) + Pb(NO3)2(aq) -------> PbCO3(s) + 2NaNO3(aq)

We have to determine the limiting reactant. This is the reactant that yields the least amount of product. Note that the spectator ions are Na^+ and NO3^- that form NaNO3.

For Na2CO3

1 mole of Na2CO3 yields 2 moles of NaNO3

3 moles of Na2CO3 yields  3 × 2/1 = 6 moles of NaNO3

For Pb(NO3)2

1 mole of Pb(NO3)2 yields 2 moles of NaNO3

2 moles of Pb(NO3)2 yields 2 × 2/1 = 4 moles of NaNO3

We can see that Pb(NO3)2 is the limiting reactant.

Since [NaNO3] = [Na^+] = [NO3^-], it follows that there are 4 moles of spectator ions that remain in solution.

Learn more: brainly.com/question/22885959

6 0
3 years ago
Please help me ASAP
MrRissso [65]

Answer:

<h2><em>an</em><em>swer</em><em> will</em><em> be</em><em> </em><em>D</em></h2>

<em>change</em><em> </em><em>of</em><em> </em><em>sta</em><em>te</em><em> </em><em>only</em><em> </em>

8 0
3 years ago
Which of these 2A elements has the largest atomic radius?
olya-2409 [2.1K]

Answer: Option (E) is the correct answer.

Explanation:

When we move from top to bottom in a group then there occurs an increase in atomic size of the atoms due to increase in the number of electrons.

For example, in group 2A elements beryllium is the smallest in size whereas radium being at the bottom is the largest in size.

Also, atomic number of beryllium is 4 and atomic number of radium is 88.

Thus, we can conclude that out of the given options radium is the 2A element which has the largest atomic radius.

5 0
4 years ago
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