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victus00 [196]
3 years ago
14

I’m trying to figure out how to convert 6 moles KCL to particles.

Chemistry
1 answer:
I am Lyosha [343]3 years ago
7 0

Answer:

How many moles KCl in 1 grams? The answer is 0.013413582325

1 mole is equal to 1 moles KCl, or 74.5513 grams.

447.3078 is the answer

Explanation:

<em>~Cornasha_Weeb</em>

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Advocard [28]

Answer:

Explanation:

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8 0
3 years ago
One difference between mixtures and pure substances is that
defon

Answer:

The mixture is made up of different atoms and pure substance is made up of same type of atom.

The main difference is that mixture can be separated into its component by physical mean while pure substances can not be separated by physical process

Explanation:

Mixture:

  • The properties of the mixture are not same and contains the properties of all those component present in it.
  • it is a combination of one or more Pure substances and can be separated by simple physical methods.
  • it have varying boiling and melting point

Examples are:

  • mixture of salt and sand
  • Salt water is mixture of water and NaCl and can be separated by physical mean.
  • Alloys: its a mixture of different metal
  • Air: mixture of gases

Pure Substance:

Pure substances are those made of same type of atoms all elements and compounds are pure substances.

  • it can not be separated by simple physical mean
  • it have very constant and consistent melting and boiling point

Examples are:

  • Water : contain only water molecule
  • All elements: all elements are pure substance made of same atoms
  • All compounds: can not be separated by physical mean.

8 0
3 years ago
Read 2 more answers
Which of these could create static electricity?
Vinil7 [7]

c well actually I remember being tought this but I cant remember it 100

6 0
3 years ago
Read 2 more answers
What is the mass of an electron?
Lesechka [4]

Answer:

the answer is 0 amu I hope it helps

6 0
3 years ago
H2(g) + Co(g) _CH3OH<br> balance the equation <br>​
Tom [10]

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

  aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

  C: 1a + 0b = 1c

  O: 1a + 0b = 1c

  H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 1

  b = 2

  c = 1

4. Substitute Coefficients and Verify Result

  CO + 2H2 = CH3OH

      L R

  C: 1 1 ✔️

  O: 1 1 ✔️

  H: 4 4 ✔️

8 0
2 years ago
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