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2 years ago

P and Q vary inversely. If P is 16.4"when Q is 123, find an equationrelating P and Q.

Mathematics

1 answer:

aev [14]2 years ago

3 0

P= k/Q
16.4= k/123
k= 16.4 * 123
k= 2017.2
Therefore, P= 2017.2/Q

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2 years ago

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Please help!!!!!!!!!!!

Assoli18 [71]

Let's take this problem step by step:

To find the ordered pair of the system:

⇒ must set both equations equal to each other

⇒ and solve for 'x'

Let's solve:

$x^2-2x+3=-2x+19\\x^2-2x+2x+3-19=0\\x^2-16=0\\(x+4)(x-4)=0$

Let's find the x-values:

$(x-4)=0\\x=4\\\\(x+4)=0\\x=-4$

Let's find f(x)'s value for each 'x':

$x=4\\f(4)=-2(4)+19=-8+19=11\\\\x=-4\\f(-4)=-2(-4)+19=8+19=27$

Answer: (4, 11), (-4,27)

Hope that helps!

#LearnwithBrainly

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1 year ago

Plz help i kind of forgot how to do this its just a review should be easy

Jet001 [13]

This is easy just find out what 5^2 equals which will be 5x5=25 (when dealing with a squared number you will always times it by itself. so if you had 10^2 it would be 100.) so now that we know 5^2 is 25 we then can add the 20 which gets 25+20=45! Hope this helps!

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