Let s be the side length of the square. The dimensions of the rectangle are three times the side of the square (i.e. 3s), and two less than the side of the square (i.e. s-2).
So, the area of this rectangle is
The area of the square is 
, and we know that the two areas are the same, so we have
The solution s=0 would lead to the extreme case where the rectangle and the square are actually a point, so we accept the solution s=3.
Answer:
a^3 - b^3.
Step-by-step explanation:
Area = length * breadth
= (a - b)(a^2 + ab + b^2)
= a(a^2 + ab + b^2) - b(a^2 + ab + b^2)
= a^3 + a^2b + ab^2 - a^2b - ab^2 - b^3
Note: the 4 middle terms cancel out. So the answer is
a^3 - b^3.
Answer:
10 square inches
Step-by-step explanation:
cost of a plain t-shirt = $10
cost of 1 square inch of design addition = $1.50
let there be x square inches of design
then cost of x square inches of design = x*cost of 1 square inch of design
= 1.50*x = 1.5x
Total cost for t-shirt with x square inches of design = cost of a plain t-shirt + cost of x square inches of design = 10 + 1.5 x
It is given that Makeeya has only $25, then total cost which can be afforded by him will be $25 only
Thus,
10 + 1.5 x = 25
=> 1.5x = 25-10 = 15
=> x = 15/1.5 = 10
Thus, Makeeya can put 10 square inches of design on her T-shirt.
Answer:
book, bread, penny, bills
Step-by-step explanation:
It takes the least amount of books to reach 1ft, then bread, penny, lastly bills
We need to compute for the length of each trophy given that one trophy is 5 inches wider than the other.
Let x be the length of the first trophy.
Let x+5 be the length of the second trophy
The solution is shown below:
x + (x + 5) = 17
x + x + 5 =17
2x =17 -5
2x = 12
x = 12/2
x=6 (for the first trophy)
x + 5 = 6+5 = 11 (for the second trophy)
The first trophy is 6 inches wide while the second trophy is 11 inches wide.
