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mylen [45]
3 years ago
6

Find all solutions and solutions in interval[0,2pi)

Mathematics
1 answer:
frutty [35]3 years ago
7 0
\bf sin(2\theta)=2sin(\theta)cos(\theta)\\\\
-------------------------------\\\\
sin(2x)-\sqrt{3}cos(x)=0\implies 2sin(x)cos(x)-cos(x)\sqrt{3}=0
\\\\\\
\stackrel{\stackrel{common}{factor}}{cos(x)}[2sin(x)-\sqrt{3}]=0\\\\
-------------------------------\\\\

\bf cos(x)=0\implies \measuredangle x=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\\\\
-------------------------------\\\\
2sin(x)-\sqrt{3}=0\implies 2sin(x)=\sqrt{3}\implies sin(x)=\cfrac{\sqrt{3}}{2}
\\\\\\
\measuredangle x=
\begin{cases}
\frac{\pi }{3}\\\\ \frac{2\pi }{3}
\end{cases}
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Answer:

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AC² = BC² + AB² - (2 × BC × AB × cosB )

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-----------------------------------------

Using the Sine rule to find ∠ A

\frac{18}{sinA} = \frac{18.9}{sin75} ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = \frac{18sin75}{18.9} , then

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evablogger [386]
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Ber [7]

Answer:

The expressions for the payment made to Mary are,

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