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3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

8 0

Answer:

three 10 factors, move 3 places to the right

Step-by-step explanation:

Olin [163]3 years ago

4 0

Answer:

sorry i dont understand either

Step-by-step explanation:

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3 years ago

Find a power series for the function, centered at c. f(x) = 1 9 − x , c = 4 f(x) = [infinity] n = 0 Incorrect: Your answer is in

Wewaii [24]

Looks like the given function is

$f(x)=\dfrac1{9-x}$

Recall that for |x| < 1, we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

We want the series to be centered around $x=4$ , so first we rearrange f(x) :

$\dfrac1{9-x}=\dfrac1{5-(x-4)}=\dfrac15\dfrac1{1-\frac{x-4}5}$

Then

$\dfrac1{9-x}=\displaystyle\frac15\sum_{n=0}^\infty\left(\frac{x-4}5\right)^n$

which converges for |(x - 4)/5| < 1, or -1 < x < 9.

4 0

4 years ago

Find the approximate value of √191 to the nearest tenth. What 2 numbers does it fall between when placed on a number line?

meriva

The approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line is between 13-13.5.

Given that,

The square root of √191.

So, the approximate value of √191 is

$= \sqrt{191} \\\\= 13.82\\\\$

= 13.8

It shows that the two numbers that should fall between at the time when place on the number line is between 13-13.5.

Therefore we can conclude that the approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line are between 13-13.5.

Learn more about the number line here: brainly.com/question/16191404

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3 years ago