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Effectus [21]
3 years ago
11

After releasing of radioactive material into.The atnosphere from.A nuclear.Powe plant in a country in 1988, the hay in that coun

try was contaminayed by radioactive.Isotope remains, how long did the famers need to.Wait to use this hay
Mathematics
1 answer:
Radda [10]3 years ago
4 0

Answer:

the question is incomplete, so I looked for a similar one:

<em>After the release of radioactive material into the atmosphere  from a nuclear power plant, the hay was contaminated by iodine  131 ( half-life, 8 days). If it is all right to feed the hay to cows  when 10% of the iodine 131 remains, how long did the farmers  need to wait to use this hay? </em>

iodine's half life (we are given x, we need to find b):

0.5A₀ = A₀eᵇˣ

x = 8 days

we eliminate A₀ from both sides

0.5 = eᵇ⁸

ln 0.5 = ln eᵇ⁸

-0.69315 = b8

b = -0.69315 / 8 = -0.08664

since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):

0.1A₀ = A₀eᵇˣ

0.1 = eᵇˣ

ln 0.1 = bx

where b = -0.08664

x = ln 0.1 / -0.08664  = -2.302585 / -0.08664  = 26.58 days

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3 years ago
A continuous random variable may assume :
vova2212 [387]

Answer:

Option A) any numerical value in an interval or collection of intervals

Step-by-step explanation:

Continuous Random Variable:

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3 years ago
A survey of 125 households was done to investigate whether households have laptops, tablets, or
riadik2000 [5.3K]

Answer:

3) 0.326

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Total Number of surveyed households =125

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Written in Probability notation: P(Laptop|No Tablet)

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4 0
3 years ago
How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid​ solution?
horsena [70]
Work in  amount of pure acid   let x = gallons of pure acid required.
then we have the equation:-

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x + 33 = 0.80x + 44
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Tom is making a rectangular garden. he decides to make the garden 30 ft long by 15 ft wide. Later, tom decides to keep the lengt
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x = width

y = area

No matter what width (x) you choose, the area (y) is going to be a multiple of 30 (the fixed length) because with two numbers being multiplied, if there is a fixed number that will always be the multiple and not the multiplier.  For example, 10 multiplied by every number 1-10 is going to be a multiple of 10.

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So if Tom chooses any of these widths (x) 5, 10, or 15, y (the area) will be a multiple of 30.

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