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3 years ago

15

What is the intersection of the sets A=(2,3,5,7,11) and B=(5,11,13,15,17)?

1 answer:

lions [1.4K]3 years ago

7 0

Umm do have any pictures to help me answer it or anything?

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Identify the vertex, focus axis of symmetry, and directrix. Then sketch the graph

Paha777 [63]

Answer:

vertex = ( -6 , -3 )

focus = $(-\frac{97}{16} ,-3)$

axis of symmetry = y = -3

directrix = x = $-\frac{95}{16}$

GRAPH :

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1 year ago

A(4,-7) B(-2,1) find AB

Natali5045456 [20]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\A(\stackrel{x_1}{4}~,~\stackrel{y_1}{-7})\qquadB(\stackrel{x_2}{-2}~,~\stackrel{y_2}{1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\AB=\sqrt{[-2-4]^2+[1-(-7)]^2}\implies AB=\sqrt{(-2-4)^2+(1+7)^2}\\\\\\AB=\sqrt{(-6)^2+8^2}\implies AB=\sqrt{36+64}\implies AB=\sqrt{100}\implies AB=10$

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3 years ago

The night watchman in a factory cannot guard both the safe in back and the cash register in front. The safe contains $6000, whil

Zolol [24]

Answer:

The guard should be positioned at the safe

Step-by-step explanation:

The night watchmen should be positioned to guard whichever place gives the highest expected value to the thief.

The expected value of robbing the safe is:

$EV_{s} = \$ 6000*0.2\\EV_{s} = \$ 1200$

The expected value of robbing the cash register is:

$EV_{r} = \$ 1000*0.8\\EV_{r} = \$ 800$

Therefore, the guard should be positioned at the safe since it yields a higher expected value to the thief in case he tries to rob it.

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2 years ago

How do you solve this for math -3/4÷(-8/5)

Natasha2012 [34]

Answer:

15/32

Step-by-step explanation:

(-3/4)÷(-8/5)

(-3/4)×(-5/8)

15/32

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3 years ago

Which inequality is equivalent to this one? y-85-2 y-8+82-2+8 oy- 8+8

vladimir2022 [97]

Answer:

The answer is the forth one , Y-8+2⩽-2+2

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2 years ago