Answer:
The equation can be written as :-
=》Cu + AgNO3 -> Ag + Cu(NO3)2
so, the term suitable for the blank is :-
" Cu (NO3) 2 "
( note the equation isn't balnced )
balanced one is :
Cu + 2 AgNO3 -> 2 Ag + Cu(NO3)2
Density=mass/volume
calculate each liquid's density and then compare them. The liquid with the higher density is denser.
Answer:
0.09460823181719888
Explanation:
Round to whatever decimal point is needed for your answer.
The solution is as follows:
The problem would only need the information of 5,600 EJ for the known sources of methane. The molar mass of methane is 16 g/mol.
802 kJ/mol(1000 J/ 1 kJ)(1 mol/16 g)(1000 g/1 kg)(x kg) = 5,600 EJ(10¹⁸ J/1 EJ)
Solving for x,
<em>x = 1.18×10¹⁴ kg of natural gas or methane</em>
I don’t know how , what class is it for?
