Answer:
mass of S₈ = 96.1146 grams
Explanation:
The balanced equation that describe the reaction is as follows:
8 Fe + S₈ ..............> 8 FeS
From the equation, we can note that:
8 moles of Fe react with 1 mole of S₈
This means that:
8 * 55.8 grams of iron react with 8 * 32 grams of S₈.
To know the mass of S₈ that will react with 167.6 grams of Fe, we will simply do cross multiplication as follows:
mass of S₈ = (167.6 * 8 * 32) / (8 * 55.8)
mass of S₈ = 96.1146 grams
Hope this helps :)
Concentration of Solutions is oftenly expressed in Molarity. Molarity is the number of moles of solute dissolved per volume of solution.
Molarity = Moles / Volume
As,
Moles = Mass / M.mass
So,
Molarity = Mass / M.mass × Volume ---- (1)
Data Given;
Volume = 0.750 L
Mass = 52 g
M.mass = 180 g/mol
Putting Values in eq.1,
Molarity = 52 g ÷ (180 g.mol⁻¹ × 0.750 L)
Molarity = 0.385 mol.L⁻¹
Answer:
Rate of forward reaction will increase.
Explanation:
Effect of change in reaction condition on equilibrium is explained by Le Chatelier's principle. According to this principle,
If an equilibrium condition of a dynamic reversible reaction is disturbed by changing concentration, temperature, pressure, volume, etc, then reaction will move will in a direction which counteract the change.
In the given reaction,
A + B ⇌ C + D
If concentration of A is increase, then reaction will move in a direction which decreases the concentration of A to reestablish the equilibrium.
As concentration A decreases in forward direction, therefore, rate of forward reaction will increase.
Answer:
Neutral atoms of each element contain an equal number of protons and electrons. The number of protons determines an element's atomic number and is used to distinguish one element from another. ... Together, the number of protons and the number of neutrons determine an element's mass number.
Explanation:
Answer:
fH = - 3,255.7 kJ/mol
Explanation:
Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.
Qsystem + Qcombustion = 0
Qsystem = heat capacity*ΔT
10000*(25.000 - 20.826) + Qc = 0
Qcombustion = - 41,740 J = - 41.74 kJ
So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:
n = mass/molar mass = 1/ 78
n = 0.01282 mol
fH = -41.74/0.01282
fH = - 3,255.7 kJ/mol