All categories

2 years ago

The light emitted from a flame is produced when electrons in an excited state

2 answers:

Studentka2010 [4]2 years ago

8 0

The light emitted from a flame is produced when electrons in an excited state releases energy as they move to lower energy States.

sesenic [268]2 years ago

7 0

Electrons in their ground state when excited absorb energy and move to higher energy states.
Absorption is when energy is absorbed by electrons and they move to a higher energy state
Emission is when electrons release that absorbed energy and move to a lower energy state
This release of energy results in emission of light from a flame
The correct answer is
Release energy as they move to lower energy states

You might be interested in

How would a solution that is labeled 5.0 M would be read as?

Ivanshal [37]

5 moles because molarity signifies number of moles dissolved in One litre of water

8 0

3 years ago

Read 2 more answers

Given the incomplete equation representing a reaction:

Akimi4 [234]

O is what should go in the blank. O stands for Oxygen.

3 0

3 years ago

Calculate the number of C atoms in 0.190 mole C6H14O.<br> can anyone help me on this one?

likoan [24]

In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6* $10^{23}$ (atoms of C in one mole) = 6.84* $10^{23}$ atoms.

8 0

2 years ago

Pls help me I don’t know what to dooooo

Ivan

Molarity = moles of solute/volume of solution in liters.

The solute here is NaCl, of which we have 46.5 g. To calculate the molarity of an NaCl solution, we need to know the number of moles of NaCl. To convert from grams to moles, we divide the mass by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of Na and Cl: 23 amu + 35 amu = 58 amu. For our purposes, we can regard amu as equivalent to grams/mole.

(46.5 g)/(58 g/mol) = 0.8017 moles NaCl.

Now that we know both the number of moles of our NaCl solute and the volume of the solution, we can calculate the molarity:

(0.8017 moles NaCl)/(2.2 L) = 0.364 M.

5 0

2 years ago

Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas

Inessa05 [86]

The relative molecular mass of the gas : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas

Solution

Graham's Law

$\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas

Input the value :

$\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol$

7 0

2 years ago