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3 years ago

The light emitted from a flame is produced when electrons in an excited state

2 answers:

Studentka2010 [4]3 years ago

8 0

The light emitted from a flame is produced when electrons in an excited state releases energy as they move to lower energy States.

sesenic [268]3 years ago

7 0

Electrons in their ground state when excited absorb energy and move to higher energy states.
Absorption is when energy is absorbed by electrons and they move to a higher energy state
Emission is when electrons release that absorbed energy and move to a lower energy state
This release of energy results in emission of light from a flame
The correct answer is
Release energy as they move to lower energy states

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<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})$
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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

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