Answer:
2.173 moles of ethanol is presented in a 100.0g sample of ethanol .
Explanation:
The amount of substance that contains as many Particles as there are atoms in exactly 12g of carbon- '12 isotope is called 1 mole '= 46 u.
Answer:
4 & 5 have the same number of elements
There are certain rules to follow when naming covalent compounds. But first, let us look at the definition of Covalent Compounds.
<h3>
What are Covalent Compounds?</h3>
When covalent bonds aid the creation of a molecule, in which the atoms have at least one similar pair of valence electrons, a covalent compound is said to have been formed.
A very common example is water (H₂O)
<h3>
How are Covalent Compounds named?</h3>
To name a covalent compound, simply list the first element in the formula using the name of the element, then name the second element by adding the suffix "ide" to the stem of the second element's name.
If there is only one atom in the molecule of the first element, then no prefix should be added.
It is to be noted that if the second element in the compound is oxygen, then we should say:
- monox<em>ide</em> instead of monoox<em>ide</em> and
- triox<em>ide</em> instead of trox<em>ide</em>, all depending on how many atoms that are involved.
See the attached for the prefixes related to the various number of atoms in the compounds.
It is to be noted that the covalent compound to be named here is not stated hence the general answer.
Learn more about naming covalent compounds at:
brainly.com/question/9841865
The density of a material is the mass of the material per unit volume. Here the weight of the same metal is 44.40g, 40.58g and 38.35g having volume 4.8 mL, 4.7 mL and 4.2 mL respectively. Thus the density of the metal as per the given data are, 
= 9.25g/mL, 
= 8.634g/mL and 
= 9.130g/mL respectively.
The equation of the standard deviation is √{∑(x - 
)÷N}
Now the mean of the density is {(9.25 + 8.634 + 9.130)/3} = 9.004 g/mL.
The difference of the density of the 1st metal sample (9.25-9.004) = 0.246 g/mL. Squaring the value = 0.060.
The difference of the density of the 2nd metal sample (9.004-8.634) =0.37 g/mL. Squaring the value = 0.136.
The difference of the density of the 3rd metal sample (9.130-9.004) = 0.126 g/mL. Squaring the value 0.015.
The total value of the squared digits = (0.060 + 0.136 + 0.015) = 0.211. By dividing the digit by 3 we get, 0.070. The standard deviation will be 
. Thus the standard deviation of the density value is 0.265g/mL.
