Two neutral atoms, one being a nonmetal and the other a metal, form an ionic bond when the nonmetal uses energy to remove valence electrons from the metal.
Since a metal is not very electronegative but a nonmetal is, the nonmetal can remove the metal’s valence electrons.
In a perfect scenario, both atoms, now ions, will have octets. An octet is formed when an ion has a full valence shell (usually noted with 8 valence electrons).
Answer:
20 m/s^2
Explanation:
given,
final velocity (v) = 6000m/s
initial velocity (u) = 0m/s
time taken (t) = 5 minutes
= 5×60second
= 300second
acceleration(a) = ?
we know that,
a = (v-u)/t
= (6000-0)/300
= 20 m/s^2
The addition of 0.1M HCl and 0.1M NaOH both of equal amounts is considered to be a neutralization reaction. A neutralization reaction is basically a double replacement reaction participated by both an acid and a base. In this case, the NaOH is the base while the HCl is the acid. The reaction will yield the following products: Water (H20) and aqueous Sodium Chloride (NaCl). Neutralization reactions always yield a salt and water as the end products.
According to the reaction equation:
Ba(OH)2 ↔ Ba2+ + 2OH-
when 0.015 M 0.015M 2*0.015M
∴ [OH-] = 0.03 m
so we can get the POH = - ㏒ [OH-]
by substitution:
∴ POH = -㏒ 0.03
= 1.52
and then we can get the PH from this formula:
PH + POH = 14
so by substitution:
∴PH = 14 - 1.52
≈ 12.48
Answer:
7.3 g (NH₄)₃PO₄
Explanation:
The balanced equation for the reaction is:
H₃PO₄ + 3 NH₃ ----> (NH₄)₃PO₄
To find the mass of ammonium phosphate ((NH₄)₃PO₄) produced, you need to (1) convert grams NH₃ to moles NH₃ (via the molar mass from the periodic table), then (2) convert moles NH₃ to moles (NH₄)₃PO₄ (via mole-to-mole ratio from balanced equation), and then (3) convert moles (NH₄)₃PO₄ to grams (NH₄)₃PO₄ (via molar mass from periodic table). Make sure to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 2 sig figs because the given value (2.5 grams) has 2 sig figs.
Molar Mass (NH₃): 14.01 g/mol + 3(1.008 g/mol)
Molar Mass (NH₃): 17.034 g/mol
Molar Mass ((NH₄)₃PO₄):
3(14.01 g/mol) + 12(1.008 g/mol) + 30.97 g/mol + 4(16.00 g/mol)
Molar Mass ((NH₄)₃PO₄): 149.096 g/mol
2.5 g NH₃ 1 mole NH₃ 1 mole (NH₄)₃PO₄ 149.096 g
--------------- x -------------------- x --------------------------- x --------------------------
17.034 g 3 moles NH₃ 1 mole (NH₄)₃PO₄
= 7.3 g (NH₄)₃PO₄