Answer:
Molar masses of X and Z
Explanation:
To determine the mole percent of a mixture ( mole percent of unknown metals = number of mole of each of them divided the total of both the unknown salt × 100) since the percent by mass is know; we the molar mass of X and Z
mole = mass given / molar mass
Answer:
0.0011 M.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of KMnO₄ = 0.0908 g
and ,
V = 0.500 L
Since ,
we know ,
m = Molecular mass of KMnO₄ = 158 g/mol
using , the above formula to calculate the moles ,
n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol
now , calculating the molarity as ,
M = n / V = 0.00057 mol / 0.500 L = 0.0011 M.
Answer:
The correct answer is option C. The unknown solution definitely has Hg22+ present.
Explanation:
In the analysis of group 1 metal cation, the unknown solution is treated with sufficient quantity of 6 M HCl solution and if group 1 metal cations are present then white precipitate of Agcl, PbCl2 or Hg2Cl2 is formed. The precipitate of PbCl2 is soluble in hot water but the other two remains insoluble after treating with hot water. Precipitate of AgCl disappears upon treatment of NH3 solution but Hg2Cl2 becomes black in the reaction with NH3. The black Colour appears due to the formation of metallic Hg.
Balanced chemical equation of the reation is -
Hg2Cl2 + 2NH3 ---------> HgNH2Cl (white ppt.) + Hg (black ppt.) + NH4Cl
Therefore, from the given information the conclusion which can be drawn is that the unknown solution definitely has Hg22+ present.
A sodium atom contains 11 protons and 12 neutrons. Also A sodium atom contains 11 protons, so its atomic number is 11
