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Doss [256]
3 years ago
6

I am a number less than 3000. When you divide me by 32, my remainder is 30. When you divide me by 58, my remainder 44. What numb

er am I?
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0
Let Q1 and Q2 be the quotients from dividing 32 and 58 respectively.Then 32 Q1 + 30 = 58 Q2 + 4432 Q1 = 58 Q2 + 1416 Q1 = 29 Q2 + 716 Q1 = (16 + 13)Q2 + 716 Q1 = 16 Q2 + 13 Q2 + 716(Q1 - Q2) = 13 Q2 + 7Because Q1 and Q2 are integers, we have to find Q2 whereby 13Q2 + 7 is divisible by 16.After some try-and-error, we get Q2 = 13.  That is 13*13 + 7 = 176Therefore, Q1 - Q2 = 11  -->  Q1 - 13 = 11  -->  Q1 = 2432*24 + 30 = 58*13 + 44 = 798.I am 798
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I need help i dot get it.
gayaneshka [121]

Answer:

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6 0
2 years ago
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What are the solutions of the equation (2x + 3)2 + 3(2x + 3) + 11 = 02 Use u substitution and the quadratic formula to solve.
Stella [2.4K]

Answer:

x=-2.4 or x= - 12/5

Step-by-step explanation:

hope that helps.

8 0
3 years ago
Patty has 8 flowerpots, and she wants to plant a different type of flower in each pot. There are 11 types of flower available at
Dominik [7]
The combination formula is given by

C(n, r) = \frac{n!}{(n-r)!r!}

C(11, 8) = \frac{11!}{(11-8)!8!}

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7 0
3 years ago
The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

3 0
2 years ago
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sukhopar [10]
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Thats the answer
8 0
3 years ago
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