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Alik [6]
3 years ago
5

A culture of bacteria has an initial population of 41000 bacteria and doubles every 5 hours. Using the formula P_t = P_0\cdot 2^

{\frac{t}{d}}P t =P 0 ⋅2 dt , where P_tP t is the population after hours, P_0P 0 is the initial population, is the time in hours and is the doubling time, what is the population of bacteria in the culture after 14 hours, ?
Mathematics
1 answer:
vodomira [7]3 years ago
3 0

Answer:

285541  

Step-by-step explanation:

According To The Question,

  • Given, A culture of bacteria has an initial population of 41000 bacteria and doubles in every 5 hours &  P_{t} = P_{i}*(2)^{\frac{d}{t} } .

Now, for the population of bacteria in the culture after 14 hours is P_{t} . We have Initial Population(P_{i})=41000 , d=14 & t=5 .

Put These Value in Above Formula, We get

P_{t} = 41000*(2)^{\frac{14}{5} }

P_{t} = 41000*2^{2.8}

P_{t} = 41000*(6.9644)

P_{t} = 285540.5847 ≈ 285541

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