Question

A culture of bacteria has an initial population of 41000 bacteria and doubles every 5 hours. Using the formula P_t = P_0\cdot 2^{\frac{t}{d}}P t =P 0 ⋅2 dt , where P_tP t is the population after hours, P_0P 0 is the initial population, is the time in hours and is the doubling time, what is the population of bacteria in the culture after 14 hours, ?

Answer 1

Answer:

285541  

Step-by-step explanation:

According To The Question,

• Given, A culture of bacteria has an initial population of 41000 bacteria and doubles in every 5 hours &  $P_{t} = P_{i}*(2)^{\frac{d}{t} }$ .

Now, for the population of bacteria in the culture after 14 hours is $P_{t}$ . We have Initial Population($P_{i}$)=41000 , d=14 & t=5 .

Put These Value in Above Formula, We get

$P_{t} = 41000*(2)^{\frac{14}{5} }$

$P_{t} = 41000*2^{2.8}$

$P_{t} = 41000*(6.9644)$

$P_{t} =$ 285540.5847 ≈ 285541