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Schach [20]
3 years ago
11

Match each trigonometric function with its Unit Circle definition. Note that Angle A is correctly oriented for the Unit Circle d

efinition, its terminal side intersects the Unit Circle at the point (x, y), and neither x nor y is equal to zero.
1. y
2. x
3. y/x
4. 1/y
5. 1/x
6. x/y

a. sin A
b. csc A
c. tan A
d. sec A
e. cos A
f. cot A

Mathematics
2 answers:
Mashutka [201]3 years ago
7 0

Answer:

The required matching is a-1, b-4, c-3, d-5, e-2, f-6.

Step-by-step explanation:

Unit Circle is circle having radius 1 units and centered at origin.

The terminal side intersects the Unit Circle at the point (x, y), and neither x nor y is equal to zero.

So, perpendicular of triangle is y, base is x and hypotenuse is 1 unit.

It a right angled triangle,

\sin A=\frac{perpendicular}{hypotenuse}\Rightarrow \frac{y}{1}=y

\csc A=\frac{1}{\sin A}=\frac{1}{y}

\tan A=\frac{perpendicular}{base}\Rightarrow \frac{y}{x}

\sec A=\frac{hypotenuse}{base}=\frac{1}{x}

\cos A=\frac{base}{hypotenuse}=\frac{x}{1}=x

\cot A=\frac{1}{\tan A}=\frac{x}{y}

Therefore the required matching is a-1, b-4, c-3, d-5, e-2, f-6.

PtichkaEL [24]3 years ago
4 0
The first diagram below shows a circle with a radius of 1 (unit circle). The circle is drawn on a Cartesian graph with (0,0) as the center of the circle.

From the second diagram, we can determine the value of sin(Θ) = y
and cos(Θ) = x

We can further deduce that
tan(Θ) = \frac{y}{x}
sec(Θ) = \frac{1}{cos(Θ)} = \frac{1}{x}
cosec(Θ) = \frac{1}{sin(Θ)} = \frac{1}{y}
cot(Θ) = \frac{cos(Θ)}{sin(Θ)} = \frac{x}{y}

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3 0
3 years ago
Read 2 more answers
PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.
worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, m\angleK=60^\circ, and m\angle M= 45^\circ

Refer the attached image.

In a triangle sum of three angles should be 180^\circ.

So,

m\angle K+m\angle L+m\angle M=180^\circ

Plugging the values of angle K and angle M, we get:

60^\circ+m\angle L+45^\circ=180^\circ

So,

m\angle L=180^\circ-105^\circ=75^\circ

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}

We get the value of 'y'

y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38

So the length of the side KM is 13.38 units.

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}

We get the value of 'x'

x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM = KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17 units

6 0
3 years ago
Read 2 more answers
What is the solution to the system of equations?<br> y= {x+3<br> x = -2
professor190 [17]

Answer:

y=1

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Step-by-step explanation:

You're given one, so solve for y by entering -2 (x) into it's equation.

y=x+3

y=-2+3

y=-1

The other is given, so you have your answer.

:)

3 0
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