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lyudmila [28]
3 years ago
11

Find the value of x.

Mathematics
2 answers:
Over [174]3 years ago
7 0

Answer:

no need to divide by 2.

Step-by-step explanation:

let's see u will understand.

solution,

x+67=180 (being straight line)

or, x=180-67

x=113 answer.

hope it'll help you.

yawa3891 [41]3 years ago
3 0

Answer:

113°

Step-by-step explanation:

x and the angle with 67° are complementary angles and their sum is equal to 180°

x + 67 = 180 subtract 67 from both sides

x = 113°

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Find the ordered pairs for the x- and y-intercepts of the equation 3x − 2y = 18 and select the appropriate option below.
horsena [70]
Pretty sure the answer is B
8 0
3 years ago
30 POINTS!!!!!!!! JoeNah, DeKobian and Evan wrote equations to calculate the amount of money in a savings account after one year
castortr0y [4]

Answer:

See the explanation for the answer to this question

Step-by-step explanation:

Let

B ---> the balance of money saved.

M ---> the amount invested in dollars

JoeNah's Equation

M=$100

B=1.5(100)=\$150

Dekobian's Equation

M=$100

B=100+0.05(100)=\$105

Evan's Equation

M=$100

B=M(1+0.05)

Substitute

B=100(1+0.05)=\$105

Dekobian's equation and Evan's equation are correct! :)

JoeNah's equation is wrong. :(

Hope this helps you!

Have a good evening!

4 0
3 years ago
What is 7.2 times 10^5 equal to.
FromTheMoon [43]
The answer to this is 720000
4 0
3 years ago
Read 2 more answers
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
Necesito ayuda con el ejercicio de abajo, es de Física
Kryger [21]
No sé qué forma quieres que lo contestes pero es 278235/133 !
4 0
2 years ago
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