How could i write 2.7 on a number line?

Misty correctly determined the equation of the linear function represented by the table of values below to be y = negative 2 x +

olasank [31]

Answer:

C

Step-by-step explanation:

y = mx + c

m = (y2 - y1 )/ (x2 - x1)

using (1 , 7) & (2,5)

y2 = 5 y1 = 7 so y2 -y1 = -2

x2 = 2 x1 = 1 so x2 - x1 = 1

m - -2/1 = -2

y = -2x + c

when x =1 y = 7

so 7 = -2 + c

=> c =9

y = -2x + 9

if ordered pairs (2, 5) and (4, 1) used

m = (1-5)/(4-2)

=> m = -4/2

=> m = -2

y = -2x + c

for x =2 y =5

5 = -2*2 + c

=> c = 9

y = -2x + 9

she would have got same equation

3 0

3 years ago

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Which number is between 7.17 x 10^4 and 8.17 10^5 A. 6.92 x 10^4 B. 7.2 x10^9 C. 7.57 x 10^3 D. 8.053 x 10^4

Serga [27]

Answer:

D. 8.053 x 10^4

Step-by-step explanation:

Given :

7.17 x 10^4 and 8.17 10^5

The number in between the two Given numbers should be greater Than 7.17*10^4 but less than 8.17*10^5

A. 6.92 x 10^4 - this is less than 7.17 * 10^4 ; hence doesn't fit in

B. 7.2 x10^9 - this is greater than both values, hence, doesn't fit in

C. 7.57 x 10^3 - this is less than 7.17*10^4 ; hence does not fit in

D. 8.053 x 10^4 - this fits in as it is greater than 7.17*10^4 and less than 8.17*10^5 ; hence, it is the correct answer.

6 0

3 years ago

What is the standard for of the number three million, sixty thousand, five hundred twenty?

Juli2301 [7.4K]

3,000,000+60,000+500+20

3 0

3 years ago

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During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u>= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]

= [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0

3 years ago

I need to pass so can somebody answer this plz

____ [38]

B. x = y

Hope this helps! :)

4 0

3 years ago

Read 2 more answers