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Anna007 [38]
3 years ago
7

What is the relationship between radioactivity and half life

Chemistry
1 answer:
Marta_Voda [28]3 years ago
7 0
In Physics, there is an inverse exponential relationship between the half-life and the radioactivity of a substance. Half-life denotes the period during which a specific substance will decrease by 1/2 through radioactive decay. It can also be described as the period during which a single radioactive atom has a 1/2 probability of decaying some time during that specific duration. The shorter the half-life, the more radioactive that substance is. For example, a radioactive substance 'A' with a half-life of 5 days will decay twice as quickly as substance 'B' with a half-life of 10 days. Radioactive decay is a form of exponential decay. In the example above. If you started out with 100g of substance 'A' (half-life of 5 days) and 100 g of substance 'B' (half-life 10 days), then after 10 days, you would have 50g of substance 'B', and only 25g of substance 'A'. Note that, in life sciences, the term 'half-life' is a pharmacalogical term, and has nothing to do with radioactive decay.
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A sample of 8.00 g of Mg(OH)2 is added to 24.2 mL of 0.205 M HNO3. How many moles of Mg(OH)2 our present after the reaction is c
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The amount of Mg(OH)2  present after the reaction is complete is 0.136 moles of Mg(OH)2.

The equation of the reaction is;

2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)

Number of moles of Mg(OH)2 = 8.00 g/58 g/mol = 0.138 moles

Number of moles of HNO3 = 0.205 M × 24.2 mL/1000 = 0.00496 moles

Given that;

2 moles of HNO3 reacts with 1 mole of Mg(OH)2

0.00496 moles of HNO3 reacts with 0.00496 moles ×  1 mole /2 moles = 0.00248 moles of Mg(OH)2

Hence, Mg(OH)2 is the reactant in excess.

The amount of Mg(OH)2 remaining = Amount present - Amount reacted

Hence; 0.138 moles - 0.00248 moles = 0.136 moles of Mg(OH)2

Learn more: brainly.com/question/9743981

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