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madreJ [45]
3 years ago
5

Explain the relationship between the depth in a fluid and the pressure at that depth.

Physics
1 answer:
Ghella [55]3 years ago
7 0

Explanation:

The pressure exerted in the fluid at that depth is given by :

P=\rho \times g\times h..............(1)

Where

\rho is the density of the fluid

g is the acceleration due to gravity

h is the depth of the fluid

It is clear from equation (1) that the pressure exerted in the fluid is directly proportional to the depth in a fluid. As the depth increases, the pressure will also increase.

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A solenoid of length 5.0 cm has a cross sectional area of 1.0 cm2 and has 300 uniformly spaced turns. The solenoid is wrapped in
OleMash [197]

The calculated mutual inductance is 8.544 x 10⁻⁵ H.

Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.

Length of the solenoid= 5.0 cm

Area of cross-section=1.0 cm²

no of spaced turns=300 turns

turns of insulated wire=180 turns

Mutual inductance (M) = μ₀μr N1N2 A/ L

                                     =(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5

                                     =79.12 x 10⁻¹⁰ x 54000 / 5

                                     =8.544 x 10⁻⁵  H

hence, the mutual inductance is 8.544 x 10⁻⁵ H.

Learn more about Mutual inductance here-

brainly.com/question/14014588

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4 0
1 year ago
What is the potential energy of a 2 kg rock sitting at the top of a 10 meter high cliff?
prisoha [69]

Answer:200J

Explanation:E=MGH

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8 0
3 years ago
A chair of weight 70.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =
Annette [7]

Answer:

94.67 N

Explanation:

Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.

At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.  

\begin{array}{l}\\\Sigma {F_y} = 0\\\\N - W - F\sin \theta = 0\\\\N = W + F\sin \theta \\\end{array}

Substituting 70 N for W, 41 N for F and \theta for 37 degrees

N=70+41sin37=94.67441595  N and rounding off to 2 decimal places

N=94.67 N

​

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