<span>On the surface of the Earth, the escape velocity is about 11.2 km/s, which is approximately 33 times the speed of sound (Mach 33) and several times the muzzle velocity of a rifle bullet (up to 1.7 km/s). However, at 9,000 km altitude in "space", it is slightly less than 7.1 km/s.</span>
Respuesta:
24m
Explicación:
Según la ecuación de movimiento
v = u + en
Dado
Velocidad final v = 12 m / s
velocidad inicial u = 0 m / s
tiempo t = 4s
Sustituir
12 = 0 + 4a
a = 12/4
a = 3 m / s²
Lo siguiente es obtener la distancia;
S = ut + 1 / 2at²
S = 0 (4) + 1/2 (3) (4) ²
S = 3 * 16/2
S = 48/2
S = 24 m
Por lo tanto, la distancia requerida es de 24 m.
Answer: A Radium
Explanation:
Thorium-232 is an alpha-emitting radionuclide, which decays to radium-228, which is a beta emitter with a half-life of about six years.
Initial velocity (u) = 0 m/s
Final velocity (v) = 25 m/s
time taken (t) = 10s
acceleration (a) = ?
Now,
Acceleration is rate of change of velocity, so formula is
a = (v - u)/t
a = (25 - 10)/10
a = 15/10
a = 1.5 m/(s^2)
Use this value of a.
Displacement is simply the change in position, or the difference in the final and initial positions:
Then
(a) ∆<em>d</em> = 5 m - 0 m = 5 m
(b) ∆<em>d</em> = 1 m - (-2 m) = 1 m + 2 m = 3 m
(c) ∆<em>d</em> = 2 m - (-2 m) = 2 m + 2 m = 4 m
(d) ∆<em>d</em> = 6 m - 2 m = 4 m
