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xenn [34]
2 years ago
5

A __________ change occurs when the bonds between atoms or molecules change and a new substance forms. nuclear permanent physica

l chemical
Physics
1 answer:
algol132 years ago
8 0
<span>A chemical change occurs when the bonds between atoms and molecules change, and a new substance forms. This chemical change may or may not be permanent and may or may not physically affect an object. However, it always affects the chemical composition.</span>
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What are two ways to increase impulse?
Pepsi [2]

Answer:

increase the time the force acts or you could increase the number of temptations.

hope this helped!

5 0
3 years ago
The charges and coordinates of two charged particles held fixed in the xy plane are: q1 = +3.3 µc, x1 = 3.5 cm, y1 = 0.50 cm, an
Readme [11.4K]
1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is
d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}
substituting the coordinates of the two charges, we get
d= \sqrt{(3.5+2)^2+(0.5-1.5)^2}=5.6~cm=0.056~m

2) Then, we can calculate the electrostatic force between the two charges q_1 and q_2, which is given by
F=k_e  \frac{q_1 q_2}{d^2}
where k_e=8.99\cdot10^{9} Nm^2C^{-2} is the Coulomb's constant.
Substituting numbers, we get 
F=8.99\cdot10^{9} Nm^2C^{-2}  \frac{(3.3\cdot10^{-6}~C) (-4\cdot10^{-6}~C)}{(0.056~m)^2} =-37.8~N
and the negative sign means the force between the two charges is attractive, because the two charges have opposite sign.
7 0
3 years ago
In an experiment what are all the parts of an experiment that remain unchanged are called<br>​
stira [4]
The answer for this question is Control Variable because it doesn’t change throughout the experiment.
3 0
3 years ago
If a tank filled with water contains a block and the height of the water above point A within the block is 0.6 meter, what's the
garri49 [273]
Given:\\\rho=1000 \frac{kg}{m^3}\\g=9.8 \frac{m}{s^2} \\h=0.6m\\\\Find:\\p=?\\\\Solution:\\\\p=\rho gh\\\\p=1000 \frac{kg}{m^3}\cdot 9.8 \frac{m}{s^2} \cdot0.6m=5880Pa=5.88kPa\\\\Correct\;is\;answer\;\;D
6 0
3 years ago
Read 2 more answers
A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The d
Sophie [7]

Answer:

3,544.375Joules

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;

Kinetic energy = 1/2mv²

m is the mass of the body

v is the velocity

For the ball carrier;

KE = 1/2(75)(6.5)²

KE = 3168.75/2

KE = 1584.375Joules

For the defender;

KE = 1/2(80)(7)²

KE = 3920/2

KE = 1960Joules

The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender

kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules

7 0
2 years ago
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