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DiKsa [7]
3 years ago
12

Calculate the wavelength (in nm) of light that produces its first minimum at an angle of 21.0° when falling on a single slit of

width 1.46 µm.
Physics
1 answer:
Cerrena [4.2K]3 years ago
7 0

To solve this problem it is necessary to apply the related concepts to the principle of overlap, specifically to single slit diffraction experiment concept.

Mathematically this can be expressed as:

dsin\theta = m\lambda

Where,

d = Width of the slit

\lambda =Wavelength

\theta = Angle relative to the original direction of the light

m = Any integer which represent the order of the equation (number of repetition of the spectrum)

To solve the problem we need to rearrange the equation and find the wavelength

\lambda = \frac{dsin\theta}{m}

Our values are given as,

d = 1.46\mu m = 1.46*10^{-6}m

\theta = 21\°

m = 1

Replacing in our equation we have,

\lambda = \frac{dsin\theta}{m}

\lambda = \frac{(1.46*10^{-6})sin(21)}{1}

\lambda = 5.232*10^{-7}m

\lambda = 523.2nm

Therefore the wavelength is 523.2nm

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In a science museum, a 140 kg brass pendulum bob swings at the end of a 16.8 m -long wire.
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The period of the pendulum is 8.2 s

Explanation:

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where

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T is the period

We notice that the period of a pendulum does not depend at all on its mass, but only on its length.

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Briefly explain the difference between being self-centered and
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Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the
MA_775_DIABLO [31]

Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

Then you have:

Mv_{1o}+mv_{2o}=(M+m)v        (1)

M: mass Betty = 40kg

m: mass of the dog = 15kg

v1o: initial speed of Betty = 3.0m/s

v2o: initial speed of the dog = 0 m/s

v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

v=\frac{Mv_{1o}+mv_{2o}}{M+m}=\frac{(40kg)(3.0m/s)+(15kg)(0m/s)}{40kg+15kg}\\\\v=2.18m/s

The speed fo both Betty and her dog is 2.18m/s

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