Question

Exercise 2.11

Answer 1

$\int 8\, dx=8x+C\\\\ 0=8\cdot1+C\\ C=-8\\ f'(x)=8x-8\\\\ \int 8x-8\, dx=4x^2-8x+C\\\\ 3=4\cdot1^2-8\cdot1+C\\ 3=4-8+C\\ C=7\\\\ \boxed{f(x)=4x^2-8x+7}$