3 years ago

Exercise 2.11

1 answer:

5 0

$\int 8\, dx=8x+C\\\\
0=8\cdot1+C\\
C=-8\\
f'(x)=8x-8\\\\
\int 8x-8\, dx=4x^2-8x+C\\\\
3=4\cdot1^2-8\cdot1+C\\
3=4-8+C\\
C=7\\\\
\boxed{f(x)=4x^2-8x+7}
$

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Hello,

This is the same method as computing for instance:

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