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Vaselesa [24]
4 years ago
15

Exercise 2.11

Mathematics
1 answer:
yan [13]4 years ago
5 0
\int 8\, dx=8x+C\\\\
0=8\cdot1+C\\
C=-8\\
f'(x)=8x-8\\\\
\int 8x-8\, dx=4x^2-8x+C\\\\
3=4\cdot1^2-8\cdot1+C\\
3=4-8+C\\
C=7\\\\
\boxed{f(x)=4x^2-8x+7}

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Stella [2.4K]

Given:

4 relations in the options.

To find:

The relation which represents a function.

Solution:

We know that, a relation is a function if there exist a unique output value for each input value.

In option A, we have two output values y=-5 and y=1 for single input value x=-1. So, it is not a function.

In option B, we have two output values y=2 and y=4 for single input value x=3. So, it is not a function.

In option C, we have two output values y=1 and y=7 for single input value x=-1. So, it is not a function.

In option D, we have unique output value for each input value. So, it is a function.

Therefore, the correct option is D.

8 0
3 years ago
The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviat
Harlamova29_29 [7]

Answer:

The bolts with diameter less than 5.57 millimeters and with diameter greater than 5.85 millimeters should be rejected.

Step-by-step explanation:

We have been given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.71 millimeters and a standard deviation of 0.08 millimeters.    

Let us find the sample score that corresponds to z-score of bottom 4%.  

From normal distribution table we got z-score corresponding to bottom 4% is -1.75 and z-score corresponding to top 4% or data above 96% is 1.75.

Upon substituting these values in z-score formula we will get our sample scores (x) as:

z=\frac{x-\mu}{\sigma}

-1.75=\frac{x-5.71}{0.08}

-1.75*0.08=x-5.71

-0.14=x-5.71

-0.14+5.71=x-5.71+5.71

5.57=x

Therefore, the bolts with diameters less than 5.57 millimeters should be rejected.

Now let us find sample score corresponding to z-score of 1.75 as upper limit.

1.75=\frac{x-5.71}{0.08}

1.75*0.08=x-5.71

0.14=x-5.71

0.14+5.71=x-5.71+5.71

5.85=x  

Therefore, the bolts with diameters greater than 5.85 millimeters should be rejected.

7 0
3 years ago
If we solve an equation for a variable x what should our final equation look like ?
Nesterboy [21]
You can solve an easy equation in your head by using the multiplication table.
6 0
3 years ago
The lengths of a certain species of fish are approximately normally distributed with a given mean ll and standard
RoseWind [281]
How are you? Ok so It probably B but I’m not sure so just wait a few minutes till someone else answers because I’m not sure
5 0
3 years ago
Read 2 more answers
Quick Question!! Help me out :)
Kipish [7]

Answer:

R:  (16, 2)

Step-by-step explanation:

Let (x, y) be the point R

(x - 10)/2 = 3       and (y + 12)/2 = 7

x - 10 = 6                     y + 12 = 14

x = 16                           y = 2

R:  (16, 2)

4 0
3 years ago
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