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3 years ago

Write each as the sum of two terms, eachin the form tn,r.a) t19,11b) t25,16c) t14,7

Mathematics

1 answer:

allsm [11]3 years ago

3 0

9514 1404 393

Answer:

a) t18,10 + t18,11

b) t24,15 + t24,16

c) t13,6 +t13,7

Step-by-step explanation:

Each term of Pascal's triangle is the sum of the two terms above it in the triangle:

tn,r = t(n-1),(r-1) +t(n-1),r

a) t19, 11 = t18,10 + t18,11

b) t25,16 = t24,15 + t24,16

c) t14,7 = t13,6 +t13,7

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The real zeros of f(x) are x = 0.3 and x = -3.3.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

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$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

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3 years ago

Write each as the sum of two terms, eachin the form tn,r.a) t19,11b) t25,16c) t14,7​

Write each as the sum of two terms, eachin the form tn,r.a) t19,11b) t25,16c) t14,7