Question

A person invested $370 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest tenth of a year would it take for the value of the account to reach $720

Answer 1

Answer:

10.6

Step-by-step explanation:

y=a(2)^t/d

Plug in

720=370(2)^t/11

Divide both sides by 370

1.945945946 = (2)^t/11

Log both

Log(1.945945946) / Log(2)

0.9604716359 = t/11

0.9604716359 x 11 = t

10.56518799 to the nearest tenth is 10.6 = t