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vazorg [7]
2 years ago
15

A person invested $370 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest ten

th of a year would it take for the value of the account to reach $720
Mathematics
1 answer:
Neko [114]2 years ago
6 0

Answer:

10.6

Step-by-step explanation:

y=a(2)^t/d

Plug in

720=370(2)^t/11

Divide both sides by 370

1.945945946 = (2)^t/11

Log both

Log(1.945945946) / Log(2)

0.9604716359 = t/11

0.9604716359 x 11 = t

10.56518799 to the nearest tenth is 10.6 = t

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Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
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Answer:

  114°

Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

  5x = 45 . . . . . . . . . divide by °, subtract 15+6x

  x = 9 . . . . . . . . . . divide by 5

The measure of exterior angle KMN is ...

  m∠KMN = (11(9) +15)° = 114°

_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

  60° +6x° +M = 180°

  (11x +15)° +M = 180°

Equating these expressions for 180° and subtracting M gives the relation we used above:

  (11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°

  (11x +15)° = 60° +6x° . . . . . . . . . . . subtract M

This is also described by "supplements to the same angle are equal."

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