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vazorg [7]
2 years ago
15

A person invested $370 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest ten

th of a year would it take for the value of the account to reach $720
Mathematics
1 answer:
Neko [114]2 years ago
6 0

Answer:

10.6

Step-by-step explanation:

y=a(2)^t/d

Plug in

720=370(2)^t/11

Divide both sides by 370

1.945945946 = (2)^t/11

Log both

Log(1.945945946) / Log(2)

0.9604716359 = t/11

0.9604716359 x 11 = t

10.56518799 to the nearest tenth is 10.6 = t

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<u>Answer:</u>

The Ranking Percentile is (B) 97.5%

<u>Explanation :</u>

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score=\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}

Substituting the values in the above equation, we find

Z-score= \frac{(694-490)}{102}=2

So, the Z-score is +2

Now, the corresponding value of Z-score 2 in the table is 0.9772

or the percentile score is 97.72 ~ 97.5 .

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