A person invested $370 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest ten
th of a year would it take for the value of the account to reach $720
1 answer:
Answer:
10.6
Step-by-step explanation:
y=a(2)^t/d
Plug in
720=370(2)^t/11
Divide both sides by 370
1.945945946 = (2)^t/11
Log both
Log(1.945945946) / Log(2)
0.9604716359 = t/11
0.9604716359 x 11 = t
10.56518799 to the nearest tenth is 10.6 = t
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