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vazorg [7]
3 years ago
15

A person invested $370 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest ten

th of a year would it take for the value of the account to reach $720
Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

10.6

Step-by-step explanation:

y=a(2)^t/d

Plug in

720=370(2)^t/11

Divide both sides by 370

1.945945946 = (2)^t/11

Log both

Log(1.945945946) / Log(2)

0.9604716359 = t/11

0.9604716359 x 11 = t

10.56518799 to the nearest tenth is 10.6 = t

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3 years ago
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Answer:

x=3.6

Step-by-step explanation:

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Can someone help me ? Its due today please
anastassius [24]

Answer:

x=3

y=5

Step-by-step explanation:

3x+2y=19

- 2x+2y=16

_____________

x=3

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6 0
3 years ago
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Find the 15th term of the arithmetic sequence -5x+3−5x+3, -9x-2−9x−2, -13x-7,.......???
Anna35 [415]

Answer:

- 61x - 67

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

d = - 9x - 2 - (- 5x + 3)

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  = - 4x - 5 and a₁ = - 5x + 3, thus

a_{15} = - 5x + 3 + 14(- 4x - 5) = - 5x + 3 - 56x - 70 = - 61x - 67

5 0
4 years ago
ALGEBRA 2 HELP PLEASE!
Tanya [424]
Pls. see attachment. I created that table for easy monitoring and understanding. 

Yellow cells are sums that are even.
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Yellow cells w/ orange texts are sums that are both even and multiples of 3.

4 0
3 years ago
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