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Hatshy [7]
3 years ago
6

104000 rounded to the nearest ten thousands

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
104,000 would have to round to 100,000 or 110,000. If it's 100,000-104,999, then it would round up. If it's 105,000-109,999, it would round up. Since it's 104,000, it would round down. It would round to 100,000. Hope this helps! :)
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Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at
Vesnalui [34]
F(x)=x^2/(x-2)(x-1), the degree of the numerator and the degree of the denominator equal and the quotient of their coefficient equal to 1(horizontal asymptote means that the lines approach a certain number when the input approaches positive or negative infinity)
and when plugging in 2 or 1 as input, the output is undefined.
8 0
3 years ago
Read 2 more answers
A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum
galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

7 0
3 years ago
For a standard normal random variable, what z-score has (a) probability 0.175 to the right?
Mumz [18]
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Explanation: 

Let S = z-score that has a probability of 0.175 to the right. 

In terms of normal distribution, the expression "probability to the right" means the probability of having a z-score of more than a particular z-score, which is Z in our definition of variable Z. In terms of equation:

P(z ≥ S) = 0.175   (1)

Equation (1) is solvable using a normal distribution calculator (like the online calculator in this link: http://stattrek.com/online-calculator/normal.aspx). However, the calculator of this type most likely provides the value of P(z ≤ Z), the probability to the left of S.

Nevertheless, we can use the following equation:

P(z ≤ S) + P(z ≥ S) = 1 
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Now using equations (1) and (2):

P(z ≤ S) = 1 - P(z ≥ S)
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Using a normal distribution calculator (like in this link: http://stattrek.com/online-calculator/normal.aspx),

P(z ≤ S) = 0.825
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Hence, the z-score of 0.935 has a probability 0.175 to the right.
7 0
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ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

Do the math in the parenthesis first

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(3+1) = 4

Rewrite the problem

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3 0
2 years ago
Change 7/8 as a fraction in simplest form
pshichka [43]

Answer:

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